14 is a solution.
Hope this helps
The given system of equations 4x + 4y = 32 and 3x + 24 = 3y has only one solution
<u>Solution:</u>
Given, system of equations are:
4x + 4y = 32 ---- eqn (1)
3x + 24 = 3y ----- eqn (2)
We have to determine whether the system has one solution, no solution, or infinitely many solutions.
Now let us solve the given system of equations to determine.
Now, eqn (1) can be written as,
4(x + y) = 32
x + y = 8
x = 8 – y
So, substitute "x" value in eqn (2) to get the value of "y"
3(8 – y) + 24 = 3y
24 – 3y + 24 = 3y
48 = 3y + 3y
y = 8
Then, x = 8 – 8 = 0
Hence we got x = 0 and y = 8
Hence, the given system of equations has only one solution (x, y) = (0, 8)
Answer:
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Step-by-step explanation:
60+x-45+x=180
60-45+2x=180
15+2x=180
2x=180-15
2x=165
x=165/2
x=82.5
Your answer is 6/25 or 0.24
Answer:
Step-by-step explanation:
option 1: x = 41
Reason:
<1 =139 { corresponding angles }
<2 = 180 - 139 = 41 ( <1 and <2 are linear pair}
x and <2 are corresponding angles.Hence x = 41
option 3 - <2 =<3 by vertical angles congruence
option 5 - <4 = <5by the alternate interior angles theorem
