All categories

3 years ago

Help me find the midpoint please, tanks :)

Mathematics

1 answer:

Anestetic [448]3 years ago

3 0

Answer:

tanks what really or thanks your such a loser right sorry but i think its real

introduce your self but please in correct spell

okay swetie

Step-by-step explanation:

good

You might be interested in

Please help you kind people

mafiozo [28]

Answer:

All I know is that the first picture is 8

Step-by-step explanation:

I know because one times eight is eight so um yeah

5 0

2 years ago

what is the solution to the equation fraction 3 over 5 n minus fraction 4 over 5 equals fraction 1 over 5 n? n = −1 n = 2 n = fr

Norma-Jean [14]

3/5n - 4/5 = 1/5n....multiply everything by 5 to get rid of the fractions
3n - 4 = n
-4 = n - 3n
-4 = -2n
-4/-2 = n
2 = n <==

4 0

3 years ago

Read 2 more answers

6 The radius of a circle is 36 millimeters.

love history [14]

Answer:

G. 226 mm

Step-by-step explanation:

C=2(3.14)(36)

8 0

2 years ago

Read 2 more answers

Which three statements describe how to find the product of 5×10^3

Vedmedyk [2.9K]

5x10x1 electrical and electrical equipment for electrical

7 0

2 years ago

Simplify: 18q2−45q+25/9q2−25.

Svet_ta [14]

Answer:

$\frac{(6q-5)}{(3q+5)}$

Step-by-step explanation:

Given: $\frac{18q^{2}-45q+25 }{9q^{2}-25 }$

Factorizing the numerator and the denominator, we have:

18 $q^{2}$ - 45q + 25 = 18 $q^{2}$ - 30q - 15q + 25

= (3q - 5)(6q - 5)

and

9 $q^{2}$ - 25 = (3q - 5)(3q + 5)

So that,

$\frac{18q^{2}-45q+25 }{9q^{2}-25 }$ = $\frac{(3q-5)(6q-5)}{(3q-5)(3q+5)}$

= $\frac{(6q-5)}{(3q+5)}$

Therefore,

$\frac{18q^{2}-45q+25 }{9q^{2}-25 }$ = $\frac{(6q-5)}{(3q+5)}$

5 0

3 years ago