Answer:
x = -1.5 y = 8.25
Step-by-step explanation:
5x + 2y - 5x - 10y = -66
8y = 66
y = 8.25
5x + 2(8.25) = 9
x = -1.5
When angles and sides are all equal
The z score that has 70.54% of the distribution area is 9.92
<h3>What is a z-score?</h3>
The z-score is a numerical measurement used in statistics to refer to how much a given value differs from the standard deviation.
For the random variable x, the z-score is;
z = (x - 11)/2
therefore, 70.54% of the area under the curve lies to the right of x,
then the area to the left of x is;
100 - 70.54 = 29.46%
From the standard table, a z-score of -0.54 will yield an area of 29.46% to the left of x.
Therefore, we get;
(x - 11)/2 = -0.54
x - 11 = -0.54(2)
x = 9.92
The z score is 9.92
Learn more about z score here;
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You need to measure the angles wich means that u use a protractor if the angle is 90 degrees is a straight angle if it is below 90 degrees is acute and if it is above 90 degrees it's obtuse
Answer: 4.5 miles
Explanation:
When you draw the situation you find two triangles.
1) Triangle to the east of the helicopter
a) elevation angle from the high school to the helicopter = depression angle from the helicopter to the high school = 20°
b) hypotensue = distance between the high school and the helicopter
c) opposite-leg to angle 20° = heigth of the helicopter
d) adyacent leg to the angle 20° = horizontal distance between the high school and the helicopter = x
2) triangle to the west of the helicopter
a) elevation angle from elementary school to the helicopter = depression angle from helicopter to the elementary school = 62°
b) distance between the helicopter and the elementary school = hypotenuse
c) opposite-leg to angle 62° = height of the helicopter
d) adyacent-leg to angle 62° = horizontal distance between the elementary school and the helicopter = 5 - x
3) tangent ratios
a) triangle with the helicpoter and the high school
tan 20° = Height / x ⇒ height = x tan 20°
b) triangle with the helicopter and the elementary school
tan 62° = Height / (5 - x) ⇒ height = (5 - x) tan 62°
c) equal the height from both triangles:
x tan 20° = (5 - x) tan 62°
x tan 20° = 5 tan 62° - x tan 62°
x tan 20° + x tan 62° = 5 tan 62°
x (tan 20° + tan 62°) = 5 tan 62°
⇒ x = 5 tant 62° / ( tan 20° + tan 62°)
⇒ x = 4,19 miles
=> height = x tan 20° = 4,19 tan 20° = 1,525 miles
4) Calculate the hypotenuse of this triangle:
hipotenuese ² = x² + height ² = (4.19)² + (1.525)² = 19.88 miles²
hipotenuse = 4.46 miles
Rounded to the nearest tenth = 4.5 miles
That is the distance between the helicopter and the high school.
