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NemiM [27]
3 years ago
8

In ΔABC, which trigonometric ratio equals 32?

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
6 0
The given answer should be "3/2", its because "32" is not possible in anyway.. 

tan C = sin C / cos C

Where sin C = 3 / 3.61

And

cos C = 2 / 3.61

Now

tan C = (3 / 3.61) / (2 / 3.61) = (3 / 3.61) x (3.61 / 2) = 3 / 2

<span>Thus tan C is the correct choice.   </span>

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a volley ball player servers the ball. The ball follows a path given by the equation y=-0.01x^2+0.5x+3 where x and y are measure
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Answer:

(a)

Distance from player should be 13.82 feet or 36.2 feet

(b)

The ball will go over the net

Step-by-step explanation:

we are given

The ball follows a path given by the equation

y=-0.01x^2+0.5x+3

where

x and y are measured in feet and the origin is on the court directly below where the player hits the ball

(a)

net height is 8 ft

so, we can set y=8

and then we can solve for x

8=-0.01x^2+0.5x+3

8\cdot \:100=-0.01x^2\cdot \:100+0.5x\cdot \:100+3\cdot \:100

800=-x^2+50x+300

-x^2+50x-500=0

x^2-50x+500=0

we can use quadratic formula

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

x=\frac{-50\pm \sqrt{50^2-4\left(-1\right)\left(-500\right)}}{2\left(-1\right)}

x=5\left(5-\sqrt{5}\right),\:x=5\left(5+\sqrt{5}\right)

x=13.82,x=36.2

So, distance from player should be 13.82 feet or 36.2 feet

(b)

we can plug x=30 and check whether y=8 ft

y=-0.01(30)^2+0.5(30)+3

y=9ft

we know that

height of net is 8 ft

so, the ball will go over the net


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4 years ago
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d1i1m1o1n [39]
The answer is 6.35. I hope that helps
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3 years ago
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