1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lana71 [14]
3 years ago
11

Can anyone guess what game i was playing by the looks of it

Mathematics
1 answer:
OLEGan [10]3 years ago
7 0

Answer:

A VR car game and an iphone

Step-by-step explanation:

:)

You might be interested in
Translate the phrase into algebraic symbols.<br><br> the sum of a number y and sixteen.
jarptica [38.1K]
The answer to this is y+16
3 0
2 years ago
What is the height of a cone with a radius of 2 inches and volume of 6 cubic inches? Round your answer to the tenths place.
kykrilka [37]
I hope this helps you

5 0
3 years ago
Read 2 more answers
Given the diagram below, Hannah writes m 1+ m 4 = 180°, m 2 + m 5 = 180°, and m 3+ m 26 = 180°. Which of the following reasons a
Paladinen [302]

Answer:

A. Definition of linear pair

Step-by-step explanation:

A linear pair of angles is formed when two lines intersect. Since angle on a straight line = 180°, angles of a linear pair sum up to 180°.

angles 1 and 4, angles 2 and 5, angles 3 and 6 are all linear pairs. Each pair = 180°.

4 0
3 years ago
Referring to the figure, find the value of x for
Naily [24]

Answer:

X=7

Step-by-step explanation:

Perimeter =2 x(length+width)

2(3x-9+x)=38

4x-9=19

4x=28

x=7

6 0
3 years ago
The Oregon Department of Health web site provides information on the cost-to-charge ratio (the percentage of billed charges that
Alekssandra [29.7K]

Answer:

We conclude that the mean cost-to-charge ratio for Oregon hospitals is lower for outpatient care than for inpatient care.

Step-by-step explanation:W

We are given with the cost-to-charge ratios for both inpatient and outpatient care in 2002 for a sample of six hospitals in Oregon below;

Hospital       2002 Inpatient Ratio         2002 Outpatient Ratio

    1                           68                                            54

    2                          100                                           75

    3                           71                                             53

    4                           74                                            56

    5                          100                                           74

    6                           83                                            71

Let \mu_1 = <u><em>mean cost-to-charge ratio for outpatient care</em></u>

\mu_2 = <u><em>mean cost-to-charge ratio for impatient care</em></u>.

SO, Null Hypothesis, H_0 : \mu_1 \geq \mu_2     {means that the mean cost-to-charge ratio for Oregon hospitals is higher or equal for outpatient care than for inpatient care}

Alternate Hypothesis, H_A : \mu_1 < \mu_2     {means that the mean cost-to-charge ratio for Oregon hospitals is lower for outpatient care than for inpatient care}

The test statistics that would be used here is <u>Two-sample t-test statistics</u> because we don't know about population standard deviations;

                         T.S. =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2}  } }  ~ t__n__1_+_n_2_-_2

where, \bar X_1 = sample mean cost-to-charge Outpatient Ratio = \frac{\sum X_1}{n_1} = 63.83

\bar X_2 = sample mean cost-to-charge Impatient Ratio = \frac{\sum X_2}{n_2} = 82.67

s_1 = sample standard deviation for Outpatient Ratio = \sqrt{\frac{\sum (X_1-\bar X_1 )^{2} }{n_1-1} } = 10.53

s_2 = sample standard deviation for Impatient Ratio = \sqrt{\frac{\sum (X_2-\bar X_2 )^{2} }{n_2-1} } = 14.33

n_1 = sample of hospital for outpatient care = 6

n_2 = sample of hospital for outpatient care = 6

Also, s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2}  }{n_1+n_2-2} } =  \sqrt{\frac{(6-1)\times 10.53^{2}+(6-1)\times 14.33^{2}  }{6+6-2} } = 12.574

So, <u><em>the test statistics</em></u>  =  \frac{(63.83-82.67)-(0)}{12.574 \times \sqrt{\frac{1}{6}+\frac{1}{6}  } }  ~ t_1_0

                                     =  -2.595

The value of t test statistics is -2.595.

<u>Now, at 5% significance level, the t table gives critical value of -1.812 at 10 degree of freedom for left-tailed test.</u>

Since, our test statistics is less than the critical value of t as -2.595 < -1.812, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that the mean cost-to-charge ratio for Oregon hospitals is lower for outpatient care than for inpatient care.

8 0
3 years ago
Other questions:
  • (a) Write 14 as a decimal.​
    15·1 answer
  • Write the value of the underlined digit 6.54
    15·2 answers
  • A shipping company borrows $70 million at 5% p.a. compound interest to build a new cruise ship. If it repays the debt after 3 ye
    5·1 answer
  • Three point zero one divided by seven
    12·1 answer
  • Solve the equation. 10.35+2.3h=-9.2
    11·2 answers
  • What is the common difference of the following sequence: -6, -2, 2, 6
    11·1 answer
  • Of 60 corn seeds that were planted, 18 of them did not sprout. What percent of the corn seeds
    6·2 answers
  • Kristy asks Lonnie to think of a number , Add 3 to it, multiply the sum by 2, and then subtract 6. Let n stand for lonnie's star
    9·2 answers
  • Find the slope of the following coordinate<br> points.<br> (4.25, 0) and (3.5, 3)
    15·1 answer
  • A __________ is a graphical summary of data previously summarized in a frequency distribution.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!