Two circles<span> of </span>radius<span> 4 are </span>tangent<span> to the </span>graph<span> of y^</span>2<span> = </span>4x<span> at the </span>point<span> (</span>1<span>, </span>2<span>). ... I know how to </span>find<span> the </span>tangent<span> line from a circle and a given </span>point<span>, but ... </span>2a2=42. a2=8. a=±2√2. Then1−xc=±2√2<span> and </span>2−yc=±2√2. ... 4 from (1,2<span>), so you could </span>find these<span> centers, and from there the</span>equations<span> of the circle
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Answer:
Step-by-step explanation:
Add 5 to both sides
x = 6
Add 3 to both sides
x = -15 +3
x = -12
Answer:0.1 is more than -3.8 so it would be >
Step-by-step explanation:
As they are similar figures,we can use the ratio of the side to find out the value of z.
The only side that both have the value indicated is 4 and 6,therefore we would use it to find the ratio.
The eqaution would be:
6/4 = z/8
3/2 = z/8
3×8 = 2z
z = 24/2
z = 12
Thus the value of z is 12.
Hope it helps!
V=(1/3)hpir^2
v=130
h=13
r=x
130=(1/3)(13)pix^2
times both sides by 3
390=13pix^2
divide both sides by 13
30=pix^2
divide both sides by pi
30/pi=x^2
sqrt both sides
x≈3.09
radius is abou 3 units
