270 cm of snow in 18hours

Pls help whoever gives me the most correct answer I'll mark brainliest

Greeley [361]

Answer:

c= 1.16n

Step-by-step explanation:

j

6 0

3 years ago

What is the square inches?

otez555 [7]

Answer:

given :-

for rectangular part: length=12in, breadth=8in

for triangular part:base=8in, height=3in

area of the given fig:

area of the given fig:area of 2 triangles +area of rectangle 

 $→2( \frac{1}{2} \times b \times h) + l \times b \\ →2( \frac{1}{2} \times 8 \times 3) + 12 \times 8 \\ →24 + 96 \\ → {120in}^{2}$ 

<h2>hope it helps you<3</h2>

<h3 />

5 0

1 year ago

How do you do Pythagorean theorem

ser-zykov [4K]

Pythagorean theorem is a^2 + b^2 = c^2
2. You are trying to find x which is c^2
so plug in the other numbers to the other letters. 9^2 + 17^2 = c^2
9^2= 81. 17^2= 289
81 + 289 = 370
370= c^2
Now all you have to do is square root the number
*square root sign* 370
19.24
c = 19.24
So, x = 19.24

6 0

3 years ago

What is 5+x^2=2x^2+13?

pshichka [43]

Take the root of both sides, and solve.

x = 2i sqrt 2, -2i sqrt 2.

4 0

2 years ago

A motorboat takes 5 hours to travel 100mi going upstream. The return trip takes 2 hours going downstream. What is the rate of th

Temka [501]

The boat went 5hours upstream, let's say it has a "still water" speed rate of "b", it went 100miles... however, going upstream is going against the current, let's say the current has a speed rate of "c"

so, when the boat was going up, it wasn't really going "b" fast, it was going " b - c " fast, because the current was eroding speed from it

now, when coming down, the return trip, well the length is the same, so the distance is also 100miles, it only took 2hrs though, because, the boat wasn't coming down "b" fast, it was coming down " b + c " fast, because the current was adding speed to it, so it came down quicker

now, recall your d = rt, distance = rate * time

$\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
upstream&100&b-c&5\\
downstream&100&b+c&2
\end{array}
\\\\\\
\begin{cases}
100=(b-c)5\\
\qquad \frac{100}{5}=b-c\\
\qquad 20=b-c\\
\qquad 20+c=\boxed{b}\\
100=(b+c)2\\
\qquad 50=b+c\\
\qquad 50=\boxed{20+c}+c
\end{cases}$

solve for "c", to see what's the current's speed

what's "b"? well 20+c = b

4 0

2 years ago

270 cm of snow in 18hours​

270 cm of snow in 18hours