Ok so assume that if you have
xy=0 then x and y=0
-1/4(x^2-4x+3)>0
multiply both sides by -4 to clear fraction (-4/-4=1)
flip sign
x^2-4x+3<0
factor
(x-3)(x-1)<0
we know that (+) times (-)=(-) and
(-) times (-)=(+) so we don't want them to be both negative, we want different sign
we cannnot have 3 since it would be (0)(2)<0 which is false
we cannot have 1 either since (-2)(0)<0 is also false
lets see if the solution is in betwen 3 and 1 or outside of 3 and 1
ltry 2
2^3-4(2)+3<0
8-8+3<0
3<0
false
therefor it is outside ie
x>3 and x<1
Answer:
y = 4/5x
Step-by-step explanation:
Her ya go!
Answer:
$30 is not a lot of Capita so every $ needs to count!
Step-by-step explanation:
Budget well.
Answer:
p=36
Step-by-step explanation:
3(6*2)=p
3(12)=p
36=p
Sorry if its hard to understand I'm new to anwering questions on brainly
