Solve for e 0.75(8+e)=2-1.25e

2 answers:

4 0

0.75(8+e)=2-1.25e
0.75(8)+(0.75)(e)=2+-1.25e
6+0.75e=2+-1.25e
0.75e+6=-1.25e+2
0.75e+6+1.25=-1.25e+2+1.25e
2e+6=2
2e+6-6=2-6
2e=-4
2e/2=-4/2
e=-2

aev [14]3 years ago

3 0

0.75(8 + e) = 2 - 1.25e

0.75(8) = 6

6 + 0.75e = 2 - 1.25e

Add 1.25e on both sides

6 + 2e = 2

Subtract 6 on both sides

2e = -4

Divide the whole thing by 2

e = -2

You might be interested in

I am having trouble figuring out this math problem. I have tried every equation that I can think of the problem states 6×-3=5×+7

stellarik [79]

You would need to combine like terms to find your answer.
6x - 3 = 5x + 7

You would subtract 5x from both sides. Remember, x = 1x
x - 3 = 7

Lastly, you would add 3 to both sides.
x = 10

I hope this helps!

8 0

4 years ago

Read 2 more answers

36% in its simplest fraction

Dmitrij [34]

Answer:

9/25

Step-by-step explanation:

5 0

3 years ago

Find the polynomial of minimum degree, with real coefficients, zeros at x=4±2⋅i and x=−8, and y-intercept at −480. Write your an

valkas [14]

Answer:

The polynomial of minimum degree is $p(x) = x^{4}-3\cdot x^{3}-44\cdot x^{2}+292\cdot x-480$ .

Step-by-step explanation:

According to the statement, we appreciate that polynomial pass through the following points:

(i) $(4 + 2\,i,0)$ , (ii) $(4 - 2\,i, 0)$ , (iii) $(-8, 0)$ , (iv) $(0, -480)$

From Algebra we know that any n-th grade polynomial can be constructed by knowing n+1 different points. Hence, the polynomial of minimum degree is a quartic function. The polynomial has the following form:

$p(x) = (x-4-2\,i)\cdot (x-4+2\,i)\cdot (x+8)\cdot (x-r_{1})$