Answer:
8sin(x)cos³(x)
Step-by-step explanation:
sin(4x) +2 sin(2x) = 2sin(2x)*cos(2x) + 2sin(2x) = 2sin(2x)(cos2x + 1)=
= 2sin(2x)(cos²x - sin²x + cos²x + sin²x)=²2sin(2x)*(2cos²x)=
= 4*2sin(x)*cos(x)*cos²(x)= 8sin(x)cos³(x)
Answer:
Look below for coordinates
Step-by-step explanation:
A: -2, 3 to A': -2, -3
B: 5, -2 to B': 5, 2
C: -5, 1 to C': -5, -1
Reflect over x-axis: (x, -y) and Reflect over y-axis: (-x, y)
Answer:
the correct solution is -8x + 9.
Step-by-step explanation:
<u>ANSWER: </u>
The solution of the two equations 2x+3y=5 and 4x - y=17 is (4, -1).
<u>SOLUTION:
</u>
Given, two linear equations are 2x + 3y = 5 → (1) and 4x – y = 17 → (2).
Let us first solve the above equations using <em>elimination process.
</em>
For elimination, one of the coefficients of variables has to be same in order to cancel them.
Now solve (1) and (2)
eqn (1)
2 → 4x + 6y = 10
eqn (2) → 4x – y = 17
(-) ----------------------------
0x + 7y = -7
y = -1
Substitute y value in (2)

So, solution of two equations is (4, -1).
<u><em>Now let us solve using substitution process.</em></u>
Then, (2) → 4x – y = 17 → 4x = 17 + y → y = 4x – 17
Now substitute y value in (1) → 2x + 3(4x – 17) = 5 → 2x + 12x – 51 = 5 → 14x = 5 + 51 → 14x = 56
x = 4
Substitute x value in (2) → y = 4(4) – 17 → y = 16 – 17 → y = -1
Hence, the solution of the two equations is (4, -1).
Given:
There exist a proportional relationship between x and y.
To find:
The equation which represents a proportional relationship between x and y.
Solution:
If there exist a proportional relationship between x and y, then


where, k is constant of proportionality.
We know that, proportional relationship passes through the origin because (0,0) satisfy
.
For x=0, check which equation has y=0.
In option A,
.
In option B,
.
In option C,
.
In option D, 
Only in option C, we have a equation of the form
with 4 as constant of proportionality and it passes through (0,0).
Therefore, the correct option is C.