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konstantin123 [22]

2 years ago

10

One ounce of olive oil costs $0.23. How much does the whole bottle cost if it contains 32 ounces?

2 answers:

Gwar [14]2 years ago

7 0

Answer:$7.36

Step-by-step explanation:

Just multiply 0.23 with 32

ollegr [7]2 years ago

4 0

The answer is 7.36
I just times it 0.23 * 32 =7.36

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Giulio holds a bag of 70 marbles in his hands. Jim blindfolds Giulio and keeps adding marbles to Giulio's bag, one at a time. Ho

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Answer:

Weber's Law

Step-by-step explanation:

Weber's law States that it is a mathematical model of the difference threshold stating that the magnitude needed to detect a physical change in a stimulus is proportional to the absolute magnitude of that stimulus. Thus, the more intense the stimulus, the greater the change that must be made in it to be noticed.

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2 years ago

Determine the value of k

KATRIN_1 [288]

Answer:

$\displaystyle k = 6$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

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Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

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Functions
Function Notation

<u>Algebra II</u>

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<u>Calculus</u>

Limits
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Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Continuous at x = 2

$\displaystyle f(x) = \left \{ {{2x^2 \ if \ x < 2} \atop {x + k \ if \ x \geq 2}} \right.$

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4 0

2 years ago

Read 2 more answers

7 times the sum of a number and 4 is the same as 8 decreased by 3 times the number. Find the number

Marrrta [24]

Answer:

7(x4) = 8-x

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is the square Root of 136 in the nearest 10th

daser333 [38]

11.6 repeating rounded is 11.7

7 0

2 years ago

What is the positive slope of the asymptote of (y+11)^2/100-(x-6)^2/4=1? The positive slope of the asymptote is .

VladimirAG [237]

Answer:

the positive slope of the asymptote = 5

Step-by-step explanation:

Given that:

$\frac{(y+11)^2}{100} -\frac{(x-6)^2}{4} =1$

Using the standard form of the equation:

$\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}= 1$

where:

(h,k) are the center of the hyperbola.

and the y term is in front of the x term indicating that the hyperbola opens up and down.

a = distance that indicates how far above and below of the center the vertices of the hyperbola are.

For the above standard equation; the equation for the asymptote is:

$y = \pm \frac{a}{b} (x-h)+k$

where;

$\frac{a}{b}$ is the slope

From above;

(h,k) = 11, 100

$a^2$ = 100

a = $\sqrt{100}$

a = 10

$b^2 =4$

b = $\sqrt{4}$

b = 2

$y = \pm \frac{10}{2} (x-11)+2$

$y = \pm 5 (x-11)+2$

y = 5x-53 , -5x -57

Since we are to find the positive slope of the asymptote: we have

$\frac{a}{b}$ to be the slope in the equation $y = \pm \frac{10}{2} (y-11)+2$

$\frac{a}{b}$ = $\frac{10}{2}$

$\frac{a}{b}$ = 5

Thus, the positive slope of the asymptote = 5

8 0

2 years ago