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3 years ago

One ounce of olive oil costs $0.23. How much does the whole bottle cost if it contains 32 ounces?

Mathematics

2 answers:

Gwar [14]3 years ago

7 0

Answer:$7.36

Step-by-step explanation:

Just multiply 0.23 with 32

ollegr [7]3 years ago

4 0

The answer is 7.36
I just times it 0.23 * 32 =7.36

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The city is planning to add a fish pond to a neighborhood park. The figure below is a drawing of the fish pond. Its scale is 1/2

faust18 [17]

Answer:

Part a) The area of the actual fish pond is $2,956.50\ ft^{2}$

Part b) The length of the fence will be $244.20\ ft$

Step-by-step explanation:

we know that

The scale drawing is

$\frac{(1/2)}{15}\frac{in}{ft}=\frac{1}{30}\frac{in}{ft}$

step 1

Find the actual dimensions of the fish pond

To find the actual dimensions divide the measure of the drawing by the scale drawing

$0.5\ in=0.5/(1/30)=15\ ft$

$1\ in=1/(1/30)=30\ ft$

$2.5\ in=2.5/(1/30)=75\ ft$

step 2

Find the area of the actual fish pond

The area of the fish pond is equal to the area of a circle p[lus the area of rectangle

$A=\pi r^{2} +bh$

we have

$r=15\ ft$

$b=75\ ft$

$h=30\ ft$

substitute

$A=(3.14)(15)^{2} +(75)(30)=2,956.50\ ft^{2}$

step 3

Find the length of the fence around the entire fish pond

The perimeter of the fish pond is equal to the circumference of a complete circle plus the length of 75 ft two times

$P=2\pir+2(75)$

we have

$r=15\ ft$

substitute

$P=2(3.14)(15)+2(75)=244.20\ ft$

3 0

3 years ago

Given that u is the midpoint of on and v is the midpoint of rn select all statements that are true

Ira Lisetskai [31]

Answer:

6,9,15

It's a triple stack

8 0

3 years ago

Solve the following system of equations by graphing. 3x - 2y = -6 - 3x - y = -12

MA_775_DIABLO [31]

9514 1404 393

Answer:

(x, y) = (2, 6)

Step-by-step explanation:

See the attachment for the graph.

4 0

3 years ago

Please help

lora16 [44]

Answer:

1) 25

2) (5+4)×2+6-(2×2)-1

Step-by-step explanation:

1) do exponents: 6×7-9×9+64,

do multiplication: 42-81+64,

do add & subtract: 25

2) (5+4)×2+6-(2×2)-1

(9)×2+6-(4)-1

18+6-4-1

=19

4 0

4 years ago

Acute △ABC with angles α, β, and γ is inscribed in a circle. Tangents to the circle at points A, B, and C intersect in points M,

SOVA2 [1]

Answer:

The measures of angles of triangle MNP are

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

step 1

Find the measure of arcs AB, BC and AC

we know that

The inscribed angle is half that of the arc it comprises.

$\gamma=\frac{1}{2}[arc\ AB] ----> arc\ AB=2\gamma\\\alpha=\frac{1}{2}[arc\ BC] ----> arc\ BC=2\alpha\\\beta=\frac{1}{2}[arc\ AC] ----> arc\ AC=2\beta$

step 2

Find the measure of angle M

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

$M=\frac{1}{2}[arc\ AB+arc\ BC-arc\ AC]$

substitute

$M=\frac{1}{2}[2\gamma+2\alpha-2\beta]\\M=[\gamma+\alpha-\beta]$

step 3

Find the measure of angle N

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

$N=\frac{1}{2}[arc\ AC+arc\ BC-arc\ AB]$

substitute

$N=\frac{1}{2}[2\beta+2\alpha-2\gamma]\\N=[\beta+\alpha-\gamma]$

step 4

Find the measure of angle P

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

$P=\frac{1}{2}[arc\ AC+arc\ AB-arc\ BC]$

substitute

$P=\frac{1}{2}[2\beta+2\gamma-2\alpha]\\P=[\beta+\gamma-\alpha]$

5 0

3 years ago