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Vlad [161]
3 years ago
7

Rewrite the expression as an algebraic expression in x. tan(sin−1(x))

Mathematics
1 answer:
solmaris [256]3 years ago
7 0
Let tan^{-1} x=\alpha
Then it can be shown by using a right-angled triangle and the rule of Pythagoras that \alpha= tan^{-1} \frac{x}{ \sqrt{1-x^{2}} }
Therefore
tan(sin ^{-1} (x))=\frac{x}{ \sqrt{1-x^{2}} }
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Solve for x<br> 2/(7x) = 6/5<br><br> 5/21<br> -21/5<br> 21/5<br> I don't know<br> - 5/21
djverab [1.8K]
The answer is:  [A]:  " \frac{5}{21} " .
________________________________________
Given: 

2/ (7x) = 6/5; 

→  (6/5) * (7x) = 2 ; 

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x = 10/42 = (10÷2) / (42÷2) = 5/21 ; 

x = \frac{5}{21} ;

→  which is:  Answer choice:  [A]:  " \frac{5}{21} " .
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