D is the right answer F T - T
Answer:
x=6
Step-by-step explanation:
Since this is a right triangle we can use the Pythagorean theorem
a^2 + b^2 = c^2
where a and b are the legs and c is the hypotenuse
x^2 + (x+2)^2 = (2x-2)^2
FOIL (x+2)^2 = x^2 +2x+2x+4 = x^2 +4x+4
FOIL (2x-2)^2 = 4x^2 -4x -4x+4 = 4x^2 -8x+4
Replacing these in to the equation
x^2 +x^2 +4x+4 = 4x^2 -8x+4
Combine like terms
2x^2 +4x +4 = 4x^2 -8x +4
Subtract 4 from each side
2x^2 +4x +4-4 = 4x^2 -8x +4-4
2x^2 +4x = 4x^2 -8x
Subtract 2x^2 from each side
2x^2 -2x^2+4x = 4x^2-2x^2 -8x
4x = 2x^2 -8x
Subtract 4x from each side
4x-4x = 2x^2 -8x-4x
0 = 2x^2 -12x
Factor out a 2x
0 = 2x(x-6)
Using the zero product property
2x =0 x-6 =0
x =0 x-6+6 = 0+6
x = 0 c=6
Answer:
4 dimes an 7 pennies
Step-by-step explanation:
it should be easy
Answer:
The answer is terminating!
Step-by-step explanation:
repeating never ends
Answer:
The third score must be larger than or equal to 72, and smaller than or equal 87
Step-by-step explanation:
Let's name "x" the third quiz score for which we need to find the values to get the desired average.
Recalling that average grade for three quizzes is the addition of the values on each, divided by the number of quizzes (3), we have the following expression for the average:

SInce we want this average to be in between 80 and 85, we write the following double inequality using the symbols that include equal sign since we are requested the average to be between 80 and 85 inclusive:

Now we can proceed to solve for the unknown "x" treating each inaquality at a time:

This inequality tells us that the score in the third quiz must be larger than or equal to 72.
Now we study the second inequality to find the other restriction on "x":

This ine
quality tells us that the score in the third test must be smaller than or equal to 87 to reach the goal.
Therefore to obtained the requested condition for the average, the third score must be larger than or equal to 72, and smaller than or equal 87: