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Vlad [161]
3 years ago
7

Rewrite the expression as an algebraic expression in x. tan(sin−1(x))

Mathematics
1 answer:
solmaris [256]3 years ago
7 0
Let tan^{-1} x=\alpha
Then it can be shown by using a right-angled triangle and the rule of Pythagoras that \alpha= tan^{-1} \frac{x}{ \sqrt{1-x^{2}} }
Therefore
tan(sin ^{-1} (x))=\frac{x}{ \sqrt{1-x^{2}} }
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