Rewrite the expression as an algebraic expression in x. tan(sin−1(x))

1 answer:

7 0

Let $tan^{-1} x=\alpha$
Then it can be shown by using a right-angled triangle and the rule of Pythagoras that $\alpha= tan^{-1} \frac{x}{ \sqrt{1-x^{2}} }$
Therefore
$tan(sin ^{-1} (x))=\frac{x}{ \sqrt{1-x^{2}} }$

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