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Volgvan
3 years ago
11

Hi. I need some help on 15 and 16! Thank you!

Mathematics
1 answer:
Alenkinab [10]3 years ago
7 0

Answer:

MN = 34, x = 7

Step-by-step explanation:

look at the file, cut off numbers are:

37

37

36

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Is that better is just need help
yawa3891 [41]
#1 Mrs. Garcia is making 50 snacks for her 5th grade class. If she uses four 1-kilogram bags of dried fruit, how many of grams of fruit will she use for each snack? 

1 kilogram is equal to 1000 grams.
4 kilograms is equal to 4000 grams. 

You would need to divide the 4000 total grams by the 50 snack to get how many grams would be in each snack.
So you would do..

4000grams/50snacks = 80 grams each snack.

#3 Toni's recipe also calls for seasonings. She needs to stir in 215 milligrams of pepper and 437 milligrams of salt. What is the difference between the total amount of seasonings and 1 gram?

215 milligrams is equal to 0.215 grams
437 milligrams is equal to 0.437 grams 

So you would add these two together
0.215 + 0.437 = 0.652 grams
Then to find the difference you would subtract 0.652 grams from 1 gram
1 - 0.652 = 0.348 
0.348 is the difference.

5 0
3 years ago
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3. Find the range of this function.
valkas [14]

Answer:

The answer is three

Step-by-step explanation:

7 0
3 years ago
Between 60/25 and 60/132 1hich one is more bigger
nadya68 [22]

Answer:

60/25 is greater than 60/132

7 0
3 years ago
Read 2 more answers
Question: 69 = 9r -3<br> r =
In-s [12.5K]

Answer:

8 = r

Step-by-step explanation:

69 = 9r -3

Add 3 to each side

69+3 = 9r -3+3

72 = 9r

Divide each side by 9

72 / 9 = 9r/9

8 = r

4 0
3 years ago
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Suppose a random sample of size is selected from a population with . Find the value of the standard error of the mean in each of
77julia77 [94]

Answer:

A) σ_x' = 1.4142

B) σ_x' = 1.4135

C) σ_x' = 1.4073

D) σ_x' = 1.343

Step-by-step explanation:

We are given;

σ = 10

n = 50

A) when size is infinite, the standard deviation of the sample mean is given by the formula;

σ_x' = σ/√n

Thus,

σ_x' = 10/√50

σ_x' = 1.4142

B) size is given, thus, the standard deviation of the sample mean is given by the formula;

σ_x' = (σ/√n)√((N - n)/(N - 1))

Thus, with size of N = 50,000, we have;

σ_x' = 1.4142 x √((50000 - 50)/(50000 - 1))

σ_x' = 1.4142 x 0.9995

σ_x' = 1.4135

C) at N = 5000;

σ_x' = 1.4142 x √((5000 - 50)/(5000 - 1))

σ_x' = 1.4073

D) at N = 500;

σ_x' = 1.4142 x √((500 - 50)/(500 - 1))

σ_x' = 1.343

3 0
3 years ago
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