Preliminary Problem
Givens
Miles = m = 392 miles
Gallons = G = 14 gallons
Miles per gallon = mpg
Formula
miles = miles per gallon * number of gallons.
Solve
392 = mpg * 14 Divide by 14
392 / 14 = mpg
28 = mpg which is really quite good. Our vehicle gets 44 mpg but it's a 4 cylinder. It's meant to get that kind of milage.
Part A
Let x = the number of gallons used
Let y = the number of miles driven
y = k*x
Part B
y = k* x
k =28 mpg
11700 = 28*x
11700 /28 = x
x = 417.86
If this is incorrect please put some more facts in. The question does not seem complete.
Answer:
18
Step-by-step explanation:
1800.... 300 students x 6 nuggets per student= 1800 total :)
If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.
I think that the answer would be B beacuse both of them are negitive
