Take derivative..
f'(x) = 3*2*(x+4)
f'(x) is must be equal to 0.
6*(x+4)=0
x=-4
for x=-4; what is the y value?
for x=-4; f(x)=-5
the vertex is (-4,-5)<span />
Answer:
15ft
Step-by-step explanation:
Answer:
Lines c and b, f and d (option b)
Step-by-step explanation:
To prove whether the lines satisfy the condition of being a transversal to another, let's prove one of the conditions wrong, and thus the answer -
Option 1:
Here lines a and b do not correspond to one another provided they are both transversals, thus don't act as transversals to one another, they simply intersect at a given point.
Option 2:
All conditions are met, lines c and b correspond with one another such that b is a transversal to both c and d. Lines f and d correspond with one another such that f is a transversal to both d and c.
Option 3:
Lines c and d are both not transversals, thus clearly don't act as transversals to one another.
Option 4:
Lines c and d are both not transversals, thus clearly don't act as transversals to one another.
You should divide 280 into 3 which would equal 9
the value of x is 36 degree
