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3 years ago

Find the area of these shapes AND explain your method Can some one help me :((

Mathematics

2 answers:

marin [14]3 years ago

5 0

6x7=42cm squared
Base x height = triangle area
10+18=28/2=14
14x5=70cm squared
Add the parallel line together and divide that number by 2 then times that number by the height.

-Dominant- [34]3 years ago

4 0

Answer:

Triangle - 21 units

Trapezoid - 65 units

Step-by-step explanation:

Because this triangle and trapezoid are reflections of each other when split in half, remove the highlighted parts to make them a rectangle. When made into a rectangle, you can use the formula length * width to find the area of either shape (trapezoid or triangle).
Note you won't be able to do this when solving for the area of ALL trapezoids and triangles.

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Step-by-step explanation:

Formula:

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3 years ago

Given: cos θ=-4/5, sin x = -12/13, θ is in the third quadrant,

USPshnik [31]

By definition of tangent,

tan(2θ) = sin(2θ) / cos(2θ)

Recall the double angle identities:

sin(2θ) = 2 sin(θ) cos(θ)

cos(2θ) = cos²(θ) - sin²(θ) = 2 cos²(θ) - 1

where the latter equality follows from the Pythagorean identity, cos²(θ) + sin²(θ) = 1. From this identity we can solve for the unknown value of sin(θ):

sin(θ) = ± √(1 - cos²(θ))

and the sign of sin(θ) is determined by the quadrant in which the angle terminates.

We're given that θ belongs to the third quadrant, for which both sin(θ) and cos(θ) are negative. So if cos(θ) = -4/5, we get

sin(θ) = - √(1 - (-4/5)²) = -3/5

Then

tan(2θ) = sin(2θ) / cos(2θ)

tan(2θ) = (2 sin(θ) cos(θ)) / (2 cos²(θ) - 1)

tan(2θ) = (2 (-3/5) (-4/5)) / (2 (-4/5)² - 1)

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