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AfilCa [17]
2 years ago
11

Which inequality does this number line represent?

Mathematics
2 answers:
AlexFokin [52]2 years ago
6 0

Answer: n> or = -2

Step-by-step explanation:

borishaifa [10]2 years ago
4 0
I think ur right because it’s -2 and positive n and it starts at negative 2 and has n as a positive. I'm not good at math but hope we are right lol.
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Write the relation as a set of ordered pairs.
AveGali [126]

Answer:

Is B (-2,-1),(0,0),(2,1)

Step-by-step explanation:

x y

-2 -1

0 0

2 1

I think!!??

5 0
3 years ago
What would a piece 430 feet 3 inches cost if you get a 10% discount for the larger volume? A piece of wire cable 180 ½ feet long
alexgriva [62]
To get the answer to this question you would have to multiply these numbers.
The normal price appears to be 65.95 for 180.5 feet. 
First we could divide 430.25 by 180.5
This divides out to become 2.39027778.
We would then multiply This by our normal price for 180.5 feet, which is 65.95.
This gives us 157.63882.
We would next need to take the 10 percent off. The easiest way to do this is to multiply our price by .90
This would give us 141.484938.

3 0
3 years ago
Write the sentence as an equation
mel-nik [20]
Is there any answer choices so I can choose?
8 0
3 years ago
Find the value of (+328.62) – (+98.6). A. 230.02 B. 427.22 C. –427.22 D. –230.02
Jet001 [13]

Answer:

Option A - (+328.62)-(+98.6)=230.02

Step-by-step explanation:

We have given the expression (+328.62)-(+98.6)

We have to find the value of the expression ?

Solution :

Step 1 - Write the expression

=(+328.62)-(+98.6)

Step 2 - Applying symbol rule i.e. multiplication of positive into negative is always negative, (-)(+)=(-)

=328.62-98.6

Step 3 - Solve

=230.02

Therefore, The value of the expression is (+328.62)-(+98.6)=230.02

So, Option A is correct.

7 0
3 years ago
Use a proof by contradiction to show that the square root of 3 is national You may use the following fact: For any integer kirke
Ierofanga [76]

Answer:

1. Let us proof that √3 is an irrational number, using <em>reductio ad absurdum</em>. Assume that \sqrt{3}=\frac{m}{n} where  m and n are non negative integers, and the fraction \frac{m}{n} is irreducible, i.e., the numbers m and n have no common factors.

Now, squaring the equality at the beginning we get that

3=\frac{m^2}{n^2} (1)

which is equivalent to 3n^2=m^2. From this we can deduce that 3 divides the number m^2, and necessarily 3 must divide m. Thus, m=3p, where p is a non negative integer.

Substituting m=3p into (1), we get

3= \frac{9p^2}{n^2}

which is equivalent to

n^2=3p^2.

Thus, 3 divides n^2 and necessarily 3 must divide n. Hence, n=3q where q is a non negative integer.

Notice that

\frac{m}{n} = \frac{3p}{3q} = \frac{p}{q}.

The above equality means that the fraction \frac{m}{n} is reducible, what contradicts our initial assumption. So, \sqrt{3} is irrational.

2. Let us prove now that the multiplication of an integer and a rational number is a rational number. So, r\in\mathbb{Q}, which is equivalent to say that r=\frac{m}{n} where  m and n are non negative integers. Also, assume that k\in\mathbb{Z}. So, we want to prove that k\cdot r\in\mathbb{Z}. Recall that an integer k can be written as

k=\frac{k}{1}.

Then,

k\cdot r = \frac{k}{1}\frac{m}{n} = \frac{mk}{n}.

Notice that the product mk is an integer. Thus, the fraction \frac{mk}{n} is a rational number. Therefore, k\cdot r\in\mathbb{Q}.

3. Let us prove by <em>reductio ad absurdum</em> that the sum of a rational number and an irrational number is an irrational number. So, we have x is irrational and p\in\mathbb{Q}.

Write q=x+p and let us suppose that q is a rational number. So, we get that

x=q-p.

But the subtraction or addition of two rational numbers is rational too. Then, the number x must be rational too, which is a clear contradiction with our hypothesis. Therefore, x+p is irrational.

7 0
3 years ago
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