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ohaa [14]
3 years ago
11

Write a equivalent equation for the 2

Mathematics
1 answer:
Vika [28.1K]3 years ago
8 0
4x-10= 2x-5
100-30x= -15x+50
I didn’t know which one you wanted me to do so I just did both!
Hope this helps!!!
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Type your answer and then click or tap Done.<br> Simplify -(x-2y) - y.
AlladinOne [14]

Answer:

Step-by-step explanation:

x(x-2y)-(y-x)2  

Final result :

 -y2

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 x • (x - 2y) -  (y - x)2

Step  2  :

2.1     Evaluate :  (y-x)2   =    y2-2xy+x2  

Final result :

 -y2

4 0
3 years ago
Read 2 more answers
HELP PLEASE I NEED THIS FOR A TEST!!1<br> Is this a function yes or no?
sukhopar [10]
No, because the input repeated 4 twice and the output repeated 3 twice
6 0
2 years ago
Read 2 more answers
tim spends 25% of his time at the gym dooing leg exercises , 1/5 on shoulder exercises , 0.35 on biceps exercises , and warming
svetoff [14.1K]

Answer:

20%

Step-by-step explanation:

1/5 of 1 hour = 20 minutes

so 1/5 = 20%

25% + 20% = 45%

0.35 = 35%

45% + 35% = 80%

100% - 80% = 20%

Answer = 20%

Hope this helps!

3 0
4 years ago
For the function given state the period f(t) =6sin(3t-pi/6)-1
lapo4ka [179]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\&#10;% function transformations for trigonometric functions&#10;\begin{array}{rllll}&#10;% left side templates&#10;f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}&#10;\\\\&#10;f(x)=&{{  A}}cos({{  B}}x+{{  C}})+{{  D}}\\\\&#10;f(x)=&{{  A}}tan({{  B}}x+{{  C}})+{{  D}}&#10;&#10;\end{array}

\bf \begin{array}{llll}&#10;% right side info&#10;\bullet \textit{ stretches or shrinks}\\&#10;\quad \textit{horizontally by amplitude } |{{  A}}|\\\\&#10;\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\end{array}

\bf \begin{array}{llll}&#10;&#10;&#10;\bullet \textit{vertical shift by }{{  D}}\\&#10;\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{function period or frequency}\\&#10;\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\&#10;\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)&#10;\end{array}


now, with that template in mind, let's take a peek at yours

\bf \begin{array}{lllcclll}&#10;f(t)=&6sin(&3t&-\frac{\pi }{6})&-1\\&#10;&\uparrow &\uparrow &\uparrow &\uparrow \\&#10;&A&B&C&D&#10;\end{array}\\\\&#10;-----------------------------\\\\&#10;period\qquad \cfrac{2\pi }{B}\iff\cfrac{2\pi }{3}
8 0
4 years ago
4 out of every 7 students in a school eat a packed lunch. The rest eat a school meal.
strojnjashka [21]
The third one because it says 4 of 7 and the rest which is 3 eat a school meal
So the ratio is 4:3
5 0
2 years ago
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