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BigorU [14]
2 years ago
12

What are the coordinates of the point X'if the image is rotated 90° counter clockwise​

Mathematics
1 answer:
Wewaii [24]2 years ago
3 0

Step-by-step explanation:

When rotating a point 90 degrees counterclockwise about the origin our point A(x,y) becomes A'(-y,x). In other words, switch x and y and make y negative

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Jessie runs 8 yards every 2 seconds. How many feet does Jessie run in 10 seconds?
serg [7]

Answer:

40 yard

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Which table of ordered pairs represents a proportional relationship?
bogdanovich [222]

Answer:

Third table

Step-by-step explanation:

For the relationship to be proportional

y/x = constant

First table y/x = 8/4 = 2    then 7/11 doesn't =2  so it is not

Second table y/x =52/5 = 5    then 49/7 doesn't =5  so it is not

Third table y/x = 3/6=1/2    then 5/10 = 1/2   then 7/14 = 1/2  it is proportional

Last table y/x = 6/3 = 2    then 11/8 doesn't =2  so it is not

7 0
2 years ago
A figure in the first quadrant is rotated 180 counterclockwise about the origin. Which quadrant will the rotated figure appear?
blagie [28]
I believe is quadrant 3
4 0
2 years ago
Arrange these fractions in ascending order: 3/4, 2/5, 3/8, 7/10, 11/20, 23/40. Please help it’s due tomorrow and I’m big dumb
disa [49]

Answer:

3/8, 2/5, 11/20, 23/40, 7/10, 3/4

Step-by-step explanation:

Just change them all to the same denominator and you're good. Put all of the fractions' denominators to 40 as that's the least common denominator. 3/4 turns into 30/40. 2/5 turns into 16/40. 3/8 turns into 15/40. 7/10 turns into 28/40. 11/20 turns into 22/40. And 23/40 stays as it is, because the denominator is already 40.

Putting them in order is now simple,

3/8 (15/40) <  2/5 (16/40) < 11/20 (22/40) < 23/40 < 7/10 (28/40) < 3/4 (30/40)

***When you multiply any fraction to change its denominator, multiply it by the same thing to the numerator as well.

Good Luck!

8 0
3 years ago
Please help me out :P
Veseljchak [2.6K]

cos θ = \frac{-4\sqrt{65} }{65}, sin θ = \frac{-7\sqrt{65} }{65}, cot  θ  = 4/7, sec  θ = \frac{-\sqrt{65} }{4}, cosec  θ  = \frac{-\sqrt{65} }{7}

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = \sqrt{7^{2} + 4^{2} } = \sqrt{49+16} = \sqrt{65}

sin θ = opposite/ hyp = \frac{7}{\sqrt{65} }

Rationalize, \frac{7}{\sqrt{65} } x \frac{\sqrt{65} }{\sqrt{65} } = \frac{7\sqrt{65} }{65}

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - \frac{7\sqrt{65} }{65}

cos   θ  = adj/hyp = \frac{4}{\sqrt{65} }

By rationalizing and knowing that cos  θ  is negative, cos θ  = -\frac{-4\sqrt{65} }{65}

cot θ  = 1/tan θ  = 1/7/4 = 4/7

sec θ  = 1/cos θ  = 1/\frac{4}{\sqrt{65} } = -\frac{-\sqrt{65} }{4}

cosec θ  = 1/sin θ  = 1/\frac{\sqrt{65} }{7} = \frac{-\sqrt{65} }{7}

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0
1 year ago
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