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ratelena [41]
2 years ago
10

Plz help I want to ace this

Mathematics
1 answer:
nikklg [1K]2 years ago
6 0

Answer:

B

Step-by-step explanation:

You multiply the 3 numbers.

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Current rules for telephone area codes allow the use of digits​ 2-9 for the first​ digit, and​ 0-9 for the second and third​ dig
Anna35 [415]

Using the fundamental counting theorem, we have that:

  • 648 different area codes are possible with this rule.
  • There are 6,480,000,000 possible 10-digit phone numbers.
  • The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.

The fundamental counting principle states that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are ways to do both things.

For the area code:

  • 8 options for the first digit.
  • 9 options for the second and third.

Thus:

8 \times 9 \times 9 = 648

648 different area codes are possible with this rule.

For the number of 10-digit phone numbers:

  • 7 digits, each with 10 options.
  • 648 different area codes.

Then

648 \times 10^7 = 6,480,000,000


There are 6,480,000,000 possible 10-digit phone numbers.

The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.

A similar problem is given at brainly.com/question/24067651

5 0
2 years ago
Whats a square + b square I don't know thats why I am asking u dude
murzikaleks [220]

Answer:

.............................

8 0
2 years ago
Solve 3/5=8/y. Round to the nearest tenth. 15.2 9.8 13.3 18.8
Sidana [21]
3/5 = 3/y
40 = 3y
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4 0
3 years ago
What is the midline formula???
taurus [48]
The average maximum and minimum values of a formula
5 0
3 years ago
Plz help w this math problem
Svetllana [295]

Answer:

• for x = 2a√t, make t the subject:

{ \tt{x = 2a \sqrt{t} }} \\  \\ { \tt{ \sqrt{t}  =  \frac{x}{2a} }} \\  \\ { \boxed{ \tt{t =  \frac{ {x}^{2} }{4 {a}^{2} } }}}

• then find y:

{ \tt{y =  {ar}^{2}  - 2at}} \\  \\ { \tt{y =  {ar}^{2} - 2a( \frac{ {x}^{2} }{4 {a}^{2} } ) }} \\  \\ { \boxed{ \tt{y =  {ar}^{2} -  \frac{ {x}^{2} }{2a}  }}}

6 0
3 years ago
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