Answer:
You invested $22,000 in two accounts paying 3% and 5% annual interest, respectively. If the total interest earned for the year was $980, how much was invested at each rate?
Step-by-step explanation:
let x=amt invested at 3% rate of interest.
22000-x=amt invested at 5% rate of interest.
.03x+.05(22000-x)=980
.03x+1100-.05x=980
.02x=120
x=6000
22000-x=16000
amt invested at 3% rate of interest=$6,000
amt invested at 5% rate of interest=$16,000
<h2><em><u>Hope iit help you mark as Brainlist</u></em></h2>
X+5 = x^2 - x + 2
0 = x^2 -2x - 3
0 = (x-3)(x+1)
x = -1,3
y = -1 + 5 OR y = 3+5
y = 4 OR y = 8
y = 4,8
So we have two ordered pairs, (-1,4) and (3,8).
Hope that helped!
can you mark my answer as brainliest btw?
This answer would be 21 because you’d just do 15 increased by 40% which gave me 21
Answer:
26
Step-by-step explanation:
Half of 42 is 21.
21 + 5 = 26
Hope this helps you out ; )
There are 24 possible answers, 6 are correct answers and 18 are incorrect answers. By use of the hypergeometric distribution the probabilities of each possible number of randomly selected correct answers can be found, as follows:
P(0) = 0.1379, P(1) = 0.3819, P(2) = 0.341, P(3) = 0.1213, P(4) = 0.017, P(5) = 0.0008, P(6) = 0.000007.
The expected or mean number of correct answers is found from:


The answer is: 1.4998