Answer:
g(1) = 0
Step-by-step explanation:
To evaluate g(1) , substitute x = 1 into g(x), that is
g(1) = 4 - 2(3 - 1)
= 4 - 2(2)
= 4 - 4
= 0
<u>At Hayden's:</u>
<u>At Austins:</u>

As we can see in both results, it would take them
(4 hours) for the prices to be equaled.
Answer:
Yes , function is continuous in [0,2] and is differentiable (0,2) since polynomial function are continuous and differentiable
Step-by-step explanation:
We are given the Function
f(x) =
The two basic hypothesis of the mean valued theorem are
- The function should be continuous in [0,2]
- The function should be differentiable in (1,2)
upon checking the condition stated above on the given function
f(x) is continuous in the interval [0,2] as the functions is quadratic and we can conclude that from its graph
also the f(x) is differentiable in (0,2)
f'(x) = 6x - 2
Now the function satisfies both the conditions
so applying MVT
6x-2 = f(2) - f(0) / 2-0
6x-2 = 9 - 1 /2
6x-2 = 4
6x=6
x=1
so this is the tangent line for this given function.
She had 42 dollars.
(4/7 of 42 is 24 dollars)
y = mx + b
m: slope
b: y-intercept
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
3x + 9y = 18
-3x -3x
9y = -3x + 18
/9 /9
y = -3/9x + 2 OR y = -1/3 + 2
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
m = -3/9 OR -1/3
b = 2
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
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