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algol [13]
3 years ago
10

Look at this linear inequality. y≤−4x−1 Which graph shows the solution to the linear inequality?

Mathematics
1 answer:
Wittaler [7]3 years ago
4 0
Just look at the pic. U need to have the y-intercept at -1. From there you go down 4 and to the right one and plot the point.

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Which expression is equivalent to the following complex fraction? 1+1/y /1-1/y
Mrac [35]

<u>Answer:</u>

<u>\frac{y+1}{y-1}</u>

<u>Step-by-step explanation:</u>

To solve a complex fraction like \frac{(1+\frac{1}{y} )}{(1-\frac{1}{y} )}, take LCM of both the terms separately first to get:

1+\frac{1}{y} = \frac{y+1}{y}

and

1-\frac{1}{y} = \frac{y-1}{y}

Now combine and divide these terms to get:

\frac{\frac{y+1}{y} }{\frac{y-1}{y} }

The term y in both the denominators will be cancelled out by each other and you will be left with:

\frac{y+1}{y-1}

Therefore, the expression \frac{y+1}{y-1} is equivalent to the given complex fraction.

6 0
3 years ago
Read 2 more answers
Got a mind blank just wondering if im right :)<br><br> 13 + (-2)<br> = 13 - 2
yuradex [85]

Answer:

yeah then the ans is 11

Step-by-step explanation:

.........

6 0
2 years ago
Read 2 more answers
You are planning on using circles to compare the populations of California 37,691,000, Texas 25,675,000, and New York 19,465,000
Illusion [34]
The question above may be answered through the concept of ratio and proportion. The ratio between the population of a certain city and the radius of the circle used should be proportional. Mathematically, 
                             19465000/5 = 37691000/x₁ = 25,675,000/x₂
The values of x₁ and x₂ are 9.7 cm and 6.6 cm, respectively. 
5 0
3 years ago
Find the average value of the function on the given interval.<br> f(x)=(2x-1)1/2; [1,13]
Leni [432]

Answer:

The average value of the function on the given interval 6.5.

Step-by-step explanation:

Consider the given function is

f(x)=\dfrac{2x-1}{2}

We need to find the average value of the function on the given interval [1,13].

f(x)=\dfrac{2x}{2}-\dfrac{1}{2}

f(x)=x-0.5

The average value of the function f(x) on [a,b] is

Average=\dfrac{1}{b-a}\int\limits^b_a {f(x)} \, dx

Average value of the function on the given interval [1,13] is

Average=\dfrac{1}{13-1}\int\limits^{13}_{1} {x-0.5} \, dx

Average=\dfrac{1}{12}[\dfrac{x^2}{2}-0.5x]^{13}_{1}

Average=\dfrac{1}{12}[\dfrac{(13)^2}{2}-0.5(13)-(\dfrac{(1)^2}{2}-0.5(1))]

Average=\dfrac{1}{12}[78-0]

Average=6.5

Therefore, the average value of the function on the given interval 6.5.

6 0
3 years ago
Find the value of x <br><br> a. 7.5<br> b. 6<br> c. 10<br> d. 8
Radda [10]
B.6 because the length is equal to the length of the other 6
7 0
3 years ago
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