Answer:
194
Step-by-step explanation:
Answer:
your answer would be X>-4
In order to determine the area of the lot of land in squared yards, proceed as follow:
Convert the dimensions of the rectangle to yards, by using the given conversion factor:
![\begin{gathered} 7\operatorname{cm}\cdot\frac{2.5yd}{1\operatorname{cm}}=17.5yd \\ 15\operatorname{cm}\cdot\frac{2.5yd}{1\operatorname{cm}}=37.5yd \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%207%5Coperatorname%7Bcm%7D%5Ccdot%5Cfrac%7B2.5yd%7D%7B1%5Coperatorname%7Bcm%7D%7D%3D17.5yd%20%5C%5C%2015%5Coperatorname%7Bcm%7D%5Ccdot%5Cfrac%7B2.5yd%7D%7B1%5Coperatorname%7Bcm%7D%7D%3D37.5yd%20%5Cend%7Bgathered%7D)
Next, consider that the area of the lot is the area of a rectangle. Replace the previous values of the length and the width of the rectangle:
![A=(17.5yd)(37.5yd)=656.25yd^2](https://tex.z-dn.net/?f=A%3D%2817.5yd%29%2837.5yd%29%3D656.25yd%5E2)
Hence, the area of the lot of land is 656.25 sq yd
Answer:
- 400 adult tickets
- 325 children's tickets
Step-by-step explanation:
Let x represent the number of adult tickets sold. Then 725-x is the number of children's tickets sold, and the total revenue is ...
2.50x +1.50(725 -x) = 1487.50
1.00x + 1087.50 = 1487.50 . . . . . eliminate parentheses
x = 400 . . . . . . . . . . . . . . . . . . . . . subtract 1087.50
There were 400 adult tickets and 325 children's tickets sold.