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Dmitry [639]
3 years ago
11

Another one can you tell me if I did this one right

Mathematics
1 answer:
bija089 [108]3 years ago
8 0

Sorry, i dont know that one. i wish i could help ya

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Please help me with question 24 ‍♀️
love history [14]

for answer 2 is A=1/32

for answer 1 is=A=4.8

hope that helps you

3 0
3 years ago
What is the remainder of 10^2017 divided by 1001?
pashok25 [27]
Note: When I use the double equal sign, I mean the triple bar used with modular arithmetic

10^3 = 1000 == -1 (mod 1001)
10^3 == -1 (mod 1001)
(10^3)^672 == (-1)^672 (mod 1001)
(10^(3*672) == 1 (mod 1001)
10^2016 == 1 (mod 1001)
10*10^2016 == 10*1 (mod 1001)
10^2017 == 10 (mod 1001)

Final Answer: 10


5 0
3 years ago
Ted’s team score average of 23.5 points in 4 basketball games. Lauren​'s team scores an average of 75.5 points in the same 4 gam
Setler [38]

Answer:

Lauren has 52 more points than Ted.

Step-by-step explanation:

Ted- 23.5

Lauren- 75.5

75.5-23.5=52

52

5 0
3 years ago
What is the domain of the function graphed below?
I am Lyosha [343]

Answer:

x < 7

Step-by-step explanation:

the domain is the number range or interval of x the function is defined for to generate a y-value.

the graph shows that the y-values continue with x-values to the right up to but not including 7 (the empty dot says "excluding"). and with x- values to the left to negative infinity.

x=-1 is not a problem, because while for the left part of the function it is not included, but for the right part it is.

so, it is fully defined for all x < 7.

4 0
3 years ago
Find the length of the base of a square pyramid if the volume is 128 cubic inches and has a height of 6 inches
Len [333]

Answer: a = 8

Step-by-step explanation:

Volume of a square based pyramid is given as

\frac{a^{2}h }{3} .

where a is the length of the side and h is the height.

Substituting into the formula , we have

V = \frac{a^{2}h }{3}

128 = a^{2}h /3

384= a^{2} X 6

Divide through by 6

384/6 = a^{2}

64 = a^{2}

Therefore :

a = \sqrt{\frac{64}{1} }

a = 8

6 0
3 years ago
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