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3 years ago

Stuck on my Trigonometry homework :(

Mathematics

2 answers:

noname [10]3 years ago

8 0

Answer:

I think A= 60.35

Step-by-step explanation:

Hope this helped have an amazing day!

maksim [4K]3 years ago

7 0

Step-by-step explanation:

sin 23°/6cm = sin A/13cm

(sin 23°/6cm)×13cm= sin A

A= 60.35

I wish this will answer u, n im sorry if im wrong

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Please help I only need help with 16, 15, and 13. Thank you. (Number 14 is optional if you'd like to help me with that to)

telo118 [61]

Answer:

14 is 24

13 is 1.4

Step-by-step explanation:

answer 14:

First you need to add 10.1 and 1.9.

Second you need to multiply the answer you got by 4.

Last you need to divide the answer you got from the first two steps by 2.

Answer 13:

First you need to add 0.6 plus 7.4 and then multiply it by 2 because it is squared by 2.

Next you minus 14 from the answer you got from the first steps.

6 0

3 years ago

What is the answer to this math equation(x+5)(x²-3x)

Nikolay [14]

Answer:

$x=-5\\x=0\\x=3$

Step-by-step explanation:

I assume your equation to solve is

$(x+5)(x^2-3x)=0$

When we have a product of two factors equal to zero,

$A\cdot B = 0$

The solution is either A = 0 or B = 0.

In this case, this means that we can break the equation into two equations:

$x+5=0\\x^2-3x=0$

Solving the first one, we get:

$x+5=0 \rightarrow x = -5$

For the second one, we rewrite it as:

$x^2-3x=0\\x(x-3)=0$

And we see that this equation has two solutions:

$x=0\\x=3$

Therefore, the three solutions are:

$x=-5\\x=0\\x=3$

8 0

3 years ago

A rectangles width is one fifth it's length and it's perimeter is 168m. Find the dimensions of the rectangle

gayaneshka [121]

I hope this helps you

width = 1/5 .length

length =5.width

Perimeter =2 (w+l)

168=2. (w+5w)

84=6w

w=14

l=5.14=70

7 0

3 years ago

Find an ordered pair that satisfies the equation 81x + 18y = 9

ch4aika [34]

We can solve using y = 0 and solving for x.

81x + 18(0) = 9

81x = 9

x = 1/9

Therefore, the point (1/9, 0) sastisfies the equation.

Best of Luck!

4 0

3 years ago

Read 2 more answers

Find the exact value of the expression.<br> tan( sin−1 (2/3)− cos−1(1/7))

Sonja [21]

Answer:

$\tan(a-b)=\frac{2\sqrt{5}-20\sqrt{3}}{5+8\sqrt{15}}$

Step-by-step explanation:

I'm going to use the following identity to help with the difference inside the tangent function there:

$\tan(a-b)=\frac{\tan(a)-\tan(b)}{1+\tan(a)\tan(b)}$

Let $a=\sin^{-1}(\frac{2}{3})$ .

With some restriction on $a$ this means:

$\sin(a)=\frac{2}{3}$

We need to find $\tan(a)$ .

$\sin^2(a)+\cos^2(a)=1$ is a Pythagorean Identity I will use to find the cosine value and then I will use that the tangent function is the ratio of sine to cosine.

$(\frac{2}{3})^2+\cos^2(a)=1$

$\frac{4}{9}+\cos^2(a)=1$

Subtract 4/9 on both sides:

$\cos^2(a)=\frac{5}{9}$

Take the square root of both sides:

$\cos(a)=\pm \sqrt{\frac{5}{9}}$

$\cos(a)=\pm \frac{\sqrt{5}}{3}$

The cosine value is positive because $a$ is a number between $-\frac{\pi}{2}$ and $\frac{\pi}{2}$ because that is the restriction on sine inverse.

So we have $\cos(a)=\frac{\sqrt{5}}{3}$ .

This means that $\tan(a)=\frac{\frac{2}{3}}{\frac{\sqrt{5}}{3}}$ .

Multiplying numerator and denominator by 3 gives us:

$\tan(a)=\frac{2}{\sqrt{5}}$

Rationalizing the denominator by multiplying top and bottom by square root of 5 gives us:

$\tan(a)=\frac{2\sqrt{5}}{5}$

Let's continue on to letting $b=\cos^{-1}(\frac{1}{7})$ .

Let's go ahead and say what the restrictions on $b$ are.

$b$ is a number in between 0 and $\pi$ .

So anyways $b=\cos^{-1}(\frac{1}{7})$ implies $\cos(b)=\frac{1}{7}$ .

Let's use the Pythagorean Identity again I mentioned from before to find the sine value of $b$ .

$\cos^2(b)+\sin^2(b)=1$

$(\frac{1}{7})^2+\sin^2(b)=1$

$\frac{1}{49}+\sin^2(b)=1$

Subtract 1/49 on both sides:

$\sin^2(b)=\frac{48}{49}$

Take the square root of both sides:

$\sin(b)=\pm \sqrt{\frac{48}{49}$

$\sin(b)=\pm \frac{\sqrt{48}}{7}$

$\sin(b)=\pm \frac{\sqrt{16}\sqrt{3}}{7}$

$\sin(b)=\pm \frac{4\sqrt{3}}{7}$

So since $b$ is a number between $0$ and $\pi$ , then sine of this value is positive.

This implies:

$\sin(b)=\frac{4\sqrt{3}}{7}$

So $\tan(b)=\frac{\sin(b)}{\cos(b)}=\frac{\frac{4\sqrt{3}}{7}}{\frac{1}{7}}$ .

Multiplying both top and bottom by 7 gives:

$\frac{4\sqrt{3}}{1}= 4\sqrt{3}$ .

Let's put everything back into the first mentioned identity.

$\tan(a-b)=\frac{\tan(a)-\tan(b)}{1+\tan(a)\tan(b)}$

$\tan(a-b)=\frac{\frac{2\sqrt{5}}{5}-4\sqrt{3}}{1+\frac{2\sqrt{5}}{5}\cdot 4\sqrt{3}}$

Let's clear the mini-fractions by multiply top and bottom by the least common multiple of the denominators of these mini-fractions. That is, we are multiplying top and bottom by 5:

$\tan(a-b)=\frac{2 \sqrt{5}-20\sqrt{3}}{5+2\sqrt{5}\cdot 4\sqrt{3}}$

$\tan(a-b)=\frac{2\sqrt{5}-20\sqrt{3}}{5+8\sqrt{15}}$

4 0

3 years ago