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2 years ago

5

What is the correct way to reach a decision regarding a hypothesis test based on a confidence interval

1 answer:

Softa [21]2 years ago

3 0

<u>Answer</u>:

this is a multiple choice question and the answer to this question has been highlighted in bold letters.

Based on a confidence interval, the best way to get a decision on a hypothesis test is for you to fail to rej<u>e</u><u>c</u><u>t</u><u> </u><u>the </u><u>null</u><u> hypothesis</u><u> (</u><u>that </u><u>is,</u><u> </u><u>you </u><u>will</u><u> </u><u>have</u><u> to</u><u> </u><u>accept</u><u> the</u><u> null</u><u> hypothesis</u><u>)</u><u> </u><u>if </u><u>the </u><u>hypothesized</u><u> </u><u>value</u><u> </u><u>for</u><u> the</u><u> </u><u>parameter</u><u> </u><u>that </u><u>is </u><u>being</u><u> </u><u>tested</u><u> </u><u>is </u><u>within</u><u> the</u><u> </u><u>confidence</u><u> interval</u><u>.</u>

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According to Okun's law, if the unemployment rate goes from 5% to 3%, what will be the effect on the GDP?

olga2289 [7]

Answer:

D. It will increase by 1%.

Step-by-step explanation:

Given

$u_1 = 5\%$ --- initial rate

$u_2 = 3\%$ --- final rate

Required

The effect on the GDP

To calculate this, we make use of:

$\frac{\triangle Y}{Y} = u_1 - 2\triangle u$

This gives:

$\frac{\triangle Y}{Y} = 5\% - 2(5\% - 3\%)$

$\frac{\triangle Y}{Y} = 5\% - 2(2\%)$

$\frac{\triangle Y}{Y} = 5\% - 4\%$

$\frac{\triangle Y}{Y} = 1\%$

<em>This implies that the GDP will increase by 1%</em>

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3 years ago

X/3 - 4 = (-20) what is the answer

melisa1 [442]

Answer:

x=-48

Step-by-step explanation:

Add 4 to both sides and then multiply both sides by 3.

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3 years ago

Read 2 more answers

Mr. Moran chose 10 different test scores out of 50, and they are shown below. For the following set of data, find the mean test

frozen [14]

Answer:

39.5

Step-by-step explanation:

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2 years ago

I need helppppp......

Roman55 [17]

Answer:

l and n are parallel

Step-by-step explanation:

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3 years ago

An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed

masya89 [10]

Answer:

$P(X\leq 1) = 0.331$

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

$P(X = x) = \frac{y^xe^{-y}}{x!}$

Where y represents λ (average)

y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

<em />

Using probability notations;

$P(X\leq 1) = P(X=0) + P(X =1)$

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

$P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}$

$P(X = 0) = \frac{1 * e^{-2.3}}{1}$

$P(X = 0) = e^{-2.3}$

$P(X = 0) = 0.10025884372$

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

$P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}$

$P(X = 1) = \frac{2.3 * e^{-2.3}}{1}$

$P(X = 1) =2.3 * e^{-2.3}$

$P(X = 1) = 2.3 * 0.10025884372$

$P(X = 1) = 0.23059534055$

$P(X\leq 1) = P(X=0) + P(X =1)$

$P(X\leq 1) = 0.10025884372 + 0.23059534055$

$P(X\leq 1) = 0.33085418427$

$P(X\leq 1) = 0.331$

Hence, the required probability is 0.331

6 0

3 years ago