Question

(6a³-3b³)(4a²+5b²) help me please

Answer 1

So what we're going to do here is FOIL (first, inner, outer, last):

$(6 a^{3}*4 a^{2})+ (6 a^{3}*5 b^{2})+(-3 b^{3}* 4 a^{2})+(-3 b^{3}*5 b^{2})$

When we multiply exponents, and they have the same base (for example both have a or both have b), we add them. Let's simplify this expression:

$24 a^{5} +30 a^{3} b^{2}+(-12 b^{3} a^{2})+(-15 b^{5})$

Which can be further simplified to:

$24 a^{5} +30 a^{3} b^{2}-12 b^{3} a^{2}-15 b^{5}$

Answer 2

Send the question sentences.