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2 years ago

13

$14,000 is deposited into a savings account with an annual interest rate of 4% compounded continuously. How much will be in the

account after 3 years? Round to the nearest cent. $15,784.96 $15,820.00 $43,714.05 $46,481.64 if you could could you please explain thank you.

1 answer:

Svetlanka [38]2 years ago

8 0

Option A = $15,748.096
Formula for compound interest = P(1+Interest Rate)^n
=> 14000(1.04)^3
=$15,748.096

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Read 2 more answers

If n+h/5=f+9/9, then n/5=

Ann [662]

------------------------------------------------------------------
Question
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$\boxed { \frac{n+h}{5} = \frac{f+9}{9}}$

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Split the fraction on the left
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$\boxed { \frac{n}{5} + \frac{h}{5} = \frac{f + 9}{9}}$

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Take away h/5 from both sides
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$\boxed { \frac{n}{5} = \frac{f+9}{9} - \frac{h}{5}}$

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Change the denominator to be the same
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$\boxed { \frac{n}{5} = \frac{5f+45}{45} - \frac{9h}{45}}$

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Put it into single fraction
------------------------------------------------------------------
$\boxed { \frac{n}{5} = \frac{5f+45-9h}{45} }$

-------------------------------------------------------------------
Rearrange (This step may not be necessary)
------------------------------------------------------------------
$\boxed {\frac{n}{5} = \frac{5f-9h+ 45}{45} }$

$\bf \Longrightarrow \ Answer \ : \boxed {\boxed {\frac{n}{5} = \frac{5f-9h+ 45}{45} }}$

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