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3 years ago

8. The height of a ball t seconds after

Mathematics

1 answer:

Nina [5.8K]3 years ago

4 0

Answer:

B) 16

Step-by-step explanation:

We have h(t)=0, because the ball is on the ground.

So we have:

-8(2t-32)=0

2t-32=0

2t=32

t=16

It took 16 sec

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The diameter of a semicircle is 6 miles. What is the semicircle's perimeter?

koban [17]

Answer:

$15.42mi$

Step-by-step explanation:

Use the formula for a semicircle's perimeter.

$P=\frac{1}{2}\pi *d+d$

Plug in 6 for d.

$P=\frac{1}{2}\pi*6+6$

Let's use 3.14 for $\pi$ , just to make it easier, but of course, if it states to round it to something else, just plug in that many values for $\pi$ .

$P=\frac{1}{2}(3.14)*6+6 \\ \\ P=1.57*6+6 \\ \\ P=9.42+6 \\ \\ P=15.42$

5 0

3 years ago

Read 2 more answers

Given that f(x)=2x/3 evaluate f^-1(6)

abruzzese [7]

Answer:

Step-by-step explanation:

we know by definition that

$f^{-1}(f(x))=x\\\\f^{-1}(\frac{2x}{3})=x\\\\f^{-1}(x)=ax\\\\f^{-1}(\frac{2x}{3})=a(\frac{2x}{3})=x\\\\f^{-1}(x)=\frac{3x}{2}$

so now we evaluate

$f^{-1}(6)=\frac{3*6}{2}\\\\=3*3\\\\f^{-1}(6)=9$

and if we want to do an extra step

$f^{-1}(f(6))=6\\\\f^{-1}(\frac{2*6}{3})=f^{-1}(4)=\frac{3*4}{2}=6$

which works.

4 0

2 years ago

In the function y = 10.00x + 35, y represents the cost of cabin lodging per occupant and x represents the number of occupants. H

UkoKoshka [18]

Y = 10x + 35

if y is cost per occupant and x is occupants, then we can read the equation as such:

Cost is equal to 10 times number of occupants plus a 35$ fee

10 times the number of occupants is the part we are worried about

The cost increases by 10$ for every occupant

4 0

3 years ago

Read 2 more answers

A triangle has an area of 56 square units. It's night is 14 units. What is the length of its base?

NNADVOKAT [17]

Answer:

8 units

Step-by-step explanation:

b(14)/2 = 56

14b = 112

b = 8 units

4 0

3 years ago

A prticular type of tennis racket comes in a midsize versionand an oversize version. sixty percent of all customers at acertain

svetlana [45]

Answer:

a) P(x≥6)=0.633

b) P(4≤x≤8)=0.8989 (one standard deviation from the mean).

c) P(x≤7)=0.8328

Step-by-step explanation:

a) We can model this a binomial experiment. The probability of success p is the proportion of customers that prefer the oversize version (p=0.60).

The number of trials is n=10, as they select 10 randomly customers.

We have to calculate the probability that at least 6 out of 10 prefer the oversize version.

This can be calculated using the binomial expression:

$P(x\geq6)=\sum_{k=6}^{10}P(k)=P(6)+P(7)+P(8)+P(9)+P(10)\\\\\\P(x=6) = \binom{10}{6} p^{6}q^{4}=210*0.0467*0.0256=0.2508\\\\P(x=7) = \binom{10}{7} p^{7}q^{3}=120*0.028*0.064=0.215\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0168*0.16=0.1209\\\\P(x=9) = \binom{10}{9} p^{9}q^{1}=10*0.0101*0.4=0.0403\\\\P(x=10) = \binom{10}{10} p^{10}q^{0}=1*0.006*1=0.006\\\\\\P(x\geq6)=0.2508+0.215+0.1209+0.0403+0.006=0.633$

b) We first have to calculate the standard deviation from the mean of the binomial distribution. This is expressed as:

$\sigma=\sqrt{np(1-p)}=\sqrt{10*0.6*0.4}=\sqrt{2.4}=1.55$

The mean of this distribution is:

$\mu=np=10*0.6=6$

As this is a discrete distribution, we have to use integer values for the random variable. We will approximate both values for the bound of the interval.

$LL=\mu-\sigma=6-1.55=4.45\approx4\\\\UL=\mu+\sigma=6+1.55=7.55\approx8$

The probability of having between 4 and 8 customers choosing the oversize version is:

$P(4\leq x\leq 8)=\sum_{k=4}^8P(k)=P(4)+P(5)+P(6)+P(7)+P(8)\\\\\\P(x=4) = \binom{10}{4} p^{4}q^{6}=210*0.1296*0.0041=0.1115\\\\P(x=5) = \binom{10}{5} p^{5}q^{5}=252*0.0778*0.0102=0.2007\\\\P(x=6) = \binom{10}{6} p^{6}q^{4}=210*0.0467*0.0256=0.2508\\\\P(x=7) = \binom{10}{7} p^{7}q^{3}=120*0.028*0.064=0.215\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0168*0.16=0.1209\\\\\\P(4\leq x\leq 8)=0.1115+0.2007+0.2508+0.215+0.1209=0.8989$

c. The probability that all of the next ten customers who want this racket can get the version they want from current stock means that at most 7 customers pick the oversize version.

Then, we have to calculate P(x≤7). We will, for simplicity, calculate this probability substracting P(x>7) from 1.

$P(x\leq7)=1-\sum_{k=8}^{10}P(k)=1-(P(8)+P(9)+P(10))\\\\\\P(x=8) = \binom{10}{8} p^{8}q^{2}=45*0.0168*0.16=0.1209\\\\P(x=9) = \binom{10}{9} p^{9}q^{1}=10*0.0101*0.4=0.0403\\\\P(x=10) = \binom{10}{10} p^{10}q^{0}=1*0.006*1=0.006\\\\\\P(x\leq 7)=1-(0.1209+0.0403+0.006)=1-0.1672=0.8328$

7 0

3 years ago