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2 years ago

Help me answer for 11 points

Mathematics

1 answer:

Tcecarenko [31]2 years ago

4 0

Answer:

Just Transposition...

Step-by-step explanation:

12×7=84=d

92-49=43=e

28+57=85=f

96÷16=6=g

11×8=88=h

95+5-29=100-29=71=I

55-6+21=70=j

88+8÷4=96÷4=16=k

19+24-97=-97-43=54=m

-20+17+61=61+3=64=n

hope it helps

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HELP me plzzzz i need to finish this

trapecia [35]

Answer:

725.95

Step-by-step explanation:

If you multiply 129.95*5. You get 649.75, but you have to add 76.20 from the delivery and you get 725.95

Hope this helps =)

4 0

2 years ago

Pls help with steps 2 and 4!!! (Will give brainliest)

Natalka [10]

The Answer to your problem is:

#2 Answer:

13x + 7y

#4 Answer:

13x + 7y

I believe it's Distribute

6 0

2 years ago

Please help asap!! I will mark you as brainliest. :)

Ratling [72]

The measure of the angle 5 is hekdbssj and the rleation

5 0

2 years ago

Read 2 more answers

If for two non-zero vectors a,b : ∣a+b∣=∣a−b∣ then angle between them is:______a. 0b. 45c. 60d. 90

Eddi Din [679]

Answer:

$90^\circ$

Step-by-step explanation:

Given two non zero vectors, $\vec a, \vec b$ .

Let the angle between the two vectors = $\theta$

Given that:

$|\vec a+\vec b|=|\vec a-\vec b|$

Let us have a look at the formula for magnitude of addition of two vectors:

$|\vec x+\vec y|=\sqrt{x^2+y^2+2xycos\theta}$

Where $\theta$ is the angle between the two vectors.

formula for magnitude of subtraction of two vectors:

$|\vec x-\vec y|=\sqrt{x^2+y^2-2xycos\theta}$

As per the given condition:

$\sqrt{a^2+b^2+2abcos\theta}=\sqrt{a^2+b^2-2abcos\theta}$

Squaring both sides:

$a^2+b^2+2abcos\theta=a^2+b^2-2abcos\theta\\\Rightarrow 2abcos\theta=-2abcos\theta\\\Rightarrow cos\theta = -cos\theta\\\Rightarrow 2cos\theta = 0\\\Rightarrow cos\theta = 0\\\Rightarrow \theta = 90^\circ$

So, the angle between the two vectors is: $90^\circ$

7 0

2 years ago

How to solve x=5y for y

Igoryamba

$x=5y\\\\y=\frac{x}{5}$

8 0

3 years ago