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ivolga24 [154]
3 years ago
9

(-5y^2-9y-4)-(-2y^2-y+8)

Mathematics
2 answers:
Naddika [18.5K]3 years ago
5 0

Answer:

−3y2−8y−12

Step-by-step explanation:

Let's simplify step-by-step.

−5y2−9y−4−(−2y2−y+8)

Distribute the Negative Sign:

=−5y2−9y−4+−1(−2y2−y+8)

=−5y2+−9y+−4+−1(−2y2)+−1(−y)+(−1)(8)

=−5y2+−9y+−4+2y2+y+−8

Combine Like Terms:

=−5y2+−9y+−4+2y2+y+−8

=(−5y2+2y2)+(−9y+y)+(−4+−8)

=−3y2+−8y+−12

Orlov [11]3 years ago
3 0

Answer:

-3y^2-8y-12

Step-by-step explanation:

Simplify each term.

-5y^2-9y-4+2y^2+y-8

Simplify by adding terms.

-3y^2-8y-12

<em>hope this helps :)</em>

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I need help with # 14 and 15 ASAP... It is due tomorrow ..can some one please help me with it
Angelina_Jolie [31]

Answer:

See explanation

Step-by-step explanation:

A. Gasoline fill-up fee = $4.50

Cost per hour = $40

Average cost = C

Number of hours the scootcar is rented = h

Cost per h hours = $40h

Total cost = $40h + $4.50

Hence,

C = 40h+4.5

B. To plot the graph of the function, find h- and C- intercepts.

When h = 0, then C = 4.5, and we have point (0,4.5)

When C = 0, then 0 = 40h + 4.5, h = -45/400 = -0.1125, and we have point (-0.1125,0)

Plot these two points and connect them with a straight line.

Graph is attached, but you should take only that part of the graph that corresponds to points with h > 0, because the number of hours cannot be negative

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=3%28y%20-%209%29%20%3D%2030" id="TexFormula1" title="3(y - 9) = 30" alt="3(y - 9) = 30" align=
Ira Lisetskai [31]

Answer:

y=19

Step-by-step explanation:

3(y - 9) = 30

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brainliest?

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3 years ago
Quadrilateral RSTU has one pair of opposite parallel sides and one pair of opposite congruent sides as shown.
max2010maxim [7]

Answer:

A It cannot be determined from the information given.

Step-by-step explanation:

6 0
3 years ago
Suppose the number of births that occur in a hospital can be assumed to have a Poisson distribution with parameter = the average
arsen [322]

Answer:

0.5372

Step-by-step explanation:

Given that the number of births that occur in a hospital can be assumed to have a Poisson distribution with parameter = the average birth rate of 1.8 births per hour.

Let X be the no of births in the hospital per hour

X is Poisson

with mean = 1.8

the probability of observing at least two births in a given hour at the hospital

= P(X\geq 2)\\= 1-F(1)\\= 1-0.4628\\= 0.5372

the probability of observing at least two births in a given hour at the hospital = 0.5372

4 0
3 years ago
tyron and his friends go to a movie theater where large tub of popcorn costs $8 .25 and a medium soda costs $3.75 tyrone has $30
Veseljchak [2.6K]
30-8.25= 21.75


21.75/3.75= 5.8, you can't buy .8 of a soda so he could buy 5 sodas.
5 0
3 years ago
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