Question

If the if a cylinder is 7 in tall and has a volume of 63 Pi inches what is the area of the cross section it goes right down the middle

Answer 1

Answer: $9\pi \ in.^2$

Step-by-step explanation:

Given

The height of the cylinder is $h=7\ in.$

The volume of the cylinder is $V=63\pi \ in.^3$

The volume of the cylinder is the product of area and height

$\Rightarrow V=\pi r^2h$

Insert the values

$\Rightarrow 63\pi =A\times 7\\\\\Rightarrow A=\dfrac{63\pi}{7}\\\\\Rightarrow A=9\pi\ in.^2$

Thus, the area of the cross-section is $9\pi \ in.^2$