A. AAS
B. SAS
C. ASA
Just look at what order they come in. Lmk if you need further help.
Complete Question
Determine whether the normal sampling distribution can be used. The claim is p < 0.015 and the sample size is n=150
Answer:
Normal sampling distribution can not be used
Step-by-step explanation:
From the question we are told that
The null hypothesis is 
The alternative hypothesis is 
The sample size is n= 150
Generally in order to use normal sampling distribution
The value 
So


Given that
normal sampling distribution can not be used
Our repeating decimal would be= 0.5555….
Let’s give 0.5555….. repeating decimal a variable of x:
x= 0.5555…. or 0.5(move 1 point to the right)
So ,10x = 5.5555 or 5.5
Now, Let’s do subtraction:
10x = 5.5555… or 5.5
<u>- x = 0.5555… or 0.5</u>
9x
= 5.0 or 5.0
To get a fraction, provide a denominator the same with the numerator of variable x which is 9. Then divide the difference:
<span><u>9x</u> = <u>5.0</u>
9 9</span>
<span>
<span><span>
<span>
<span>Therefore, x = <u>5
</u> 9</span>
</span>
</span>
</span></span>
Step-by-step explanation:
Given that,
a)
X ~ Bernoulli
and Y ~ Bernoulli 
X + Y = Z
The possible value for Z are Z = 0 when X = 0 and Y = 0
and Z = 1 when X = 0 and Y = 1 or when X = 1 and Y = 0
If X and Y can not be both equal to 1 , then the probability mass function of the random variable Z takes on the value of 0 for any value of Z other than 0 and 1,
Therefore Z is a Bernoulli random variable
b)
If X and Y can not be both equal to 1
then,
or 
and 

c)
If both X = 1 and Y = 1 then Z = 2
The possible values of the random variable Z are 0, 1 and 2.
since a Bernoulli variable should be take on only values 0 and 1 the random variable Z does not have Bernoulli distribution