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skad [1K]
3 years ago
14

What is the answer 333​

Mathematics
2 answers:
harkovskaia [24]3 years ago
6 0

Answer:

Option A wilk be the correct answer.

Anna35 [415]3 years ago
3 0

Answer:

a. acute, equilateral

Step-by-step explanation:

From the picture the lines on the triangle mean that the sides are equivalent to one another so from that you can eliminate option c. There are not right angles within the triangle so you can eliminate option b. The angles are less than 90 degrees as they arent even cloe to being a right angle so they arent obtuse so you can eliminate option d. Now you are only left with option a.

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Which is the graph of the linear inequality x – 2y > –6?
Whitepunk [10]

Answer:

Graph the inequality by finding the boundary line, then shading the appropriate area.

y < 3 + x/2

Step-by-step explanation:

7 0
4 years ago
Consider this scenario: The population of a city increased steadily over a ten-year span. The following ordered pairs show the p
vova2212 [387]

Answer:

Regression function: y=1986.406+0.0059x

The function predicts that population will reach 14,000 in year 2068.

Step-by-step explanation:

We have to determine a function y=b_0+b_1x_1 by applying linear regression. The data we have is 5 pair of points which relates population to year.

According to the simple regression model (one independent variable), if we minimize the error between the model (the linear function) and the points given, the parameters are:

b_0=\bar{y}+b_1\bar{x}\\\\b_1=\frac{\sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}}{\sum\limits^5_{i=1} {(x_i-\bar x)^2}}

We start calculating the average of x and y

\bar x=\frac{2500+2650+3000+3500+4200}{5}=\frac{15850}{5}=3170\\\\ \bar y=\frac{2001+2002+2004+2007+2011}{5}=\frac{10025}{5}=2005

The sample covariance can be calculated as

\sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}=(2500-3170)(2001-2005)+(2650-3170)(2002-2005)+(3000-3170)(2004-2005)+(3500-3170)(2007-2005)+(4200-3170)(2011-2005)\\\\\sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}=2680+1560+170+660+6180\\\\ \sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}=11250

The variance of x can be calculated as

\sum\limits^5_{i=1} {(x_i-\bar x)^2}=(2500-3170)^2+(2650-3170)^2+(3000-3170)^2+(3500-3170)^2+(4200-3170)^2\\\\\sum\limits^5_{i=1} {(x_i-\bar x)^2}=448900+270400+28900+108900+1060900\\\\\sum\limits^5_{i=1} {(x_i-\bar x)^2}=1918000

Now we can calculate the parameters of the regression model

b_1=\frac{\sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}}{\sum\limits^5_{i=1} {(x_i-\bar x)^2}}=\frac{11250}{1918000}=0.005865485  \\\\ b_0=\bar{y}+b_1\bar{x}=2005-0.005865485*3170=1986.406413

The function then become:

y=1986.406+0.0059x

With this linear equation we can predict when the population will reach 14,000:

y=1986.406+0.0059(14,000)=1986.406+82.117=2068.523

6 0
3 years ago
Why is the number that satisfies this equation not a real number?<br> x^2=--1
Yuri [45]

Answer:

I assume that says x^2=-1, but that is the case because when we square a number, we can NEVER get a negative number. The smallest square we can get is 0. 1^2 is 1, and no real number squared gives us a negative number.

Step-by-step explanation:

4 0
3 years ago
Write an equation for this graph please help me I'm begging u
bekas [8.4K]
First, solve for the slope. This can be found by looking at the y and x intercepts. At x = 0, y = 1.5. At x = 2, y = 0.

Slope is defined as Δy/Δx, or the change in y over the change in x. This means that in order to calculate the slope, you must find the difference between the values of y and divide it by the difference in the values of x for the two points to determine the slope between them.

(0 - 1.5)/(2-0) = (-1.5)/2 = -0.75 or -3/4

Now that you have the slope, we can write the equation in slope intercept form, y = mx + b, where m is the slope we calculated and b is the y intercept, 1.5.

y = (-3/4)x + 1.5
4 0
3 years ago
The expression 6(x − 5) means the . If x = 7, the value of the expression is .
kompoz [17]

12...........................................

4 0
3 years ago
Read 2 more answers
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