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3 years ago

a deli offers up 12 different toppings on their sub sandwiches. How many different 4-topping sandwiches are possible?

Mathematics

1 answer:

jek_recluse [69]3 years ago

8 0

Answer:

There are 3 because 12 divided by 4 is 3.

Step-by-step explanation:

You might be interested in

How many permutations of the 26 letters of the English alphabet do not contain any of the strings fish, rat, or bird

NARA [144]

The number of permutations of the 26 letters of the English alphabet that do not contain any of the strings fish, rat, or bird is 402619359782336797900800000

Let

$\mathcal{E}=\{\text{All lowercase letters of the English Alphabet}\}\\\\B=\overline{\{b,i,r,d\}} \cup \{bird\}\\\\F=\overline{\{f,i,s,h\}} \cup \{fish\}\\\\R=\overline{\{r,a,t\}} \cup \{rat\}\\\\FR=\overline{\{f,i,s,h,r,a,t\}} \cup \{fish,rat\}$

Then

$Perm(\mathcal{E})=\{\text{All orderings of all the elements of } \mathcal{E}\}\\\\Perm(B)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing bird}\}\\\\Perm(F)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing fish}\}\\\\Perm(R)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing rat}\}\\\\Perm(FR)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing both fish and rat}\}\\$

Note that since

$F \cap R=\varnothing$ , $Perm(F)\cap Perm(R)\ne \varnothing$

But since

$B \cap R \ne \varnothing$ , $Perm(B)\cap Perm(R)= \varnothing$

and

$B \cap F \ne \varnothing$ , $Perm(B)\cap Perm(F)= \varnothing$

Since

$|\mathcal{E} |=26 \text{, then, } |Perm(\mathcal{E})|=26! \\\\|B|=26-4+1=23 \text{, then, } |Perm(B)|=23!\\\\|F|=26-4+1=23 \text{, then, } |Perm(F)|=23!\\\\|R|=26-3+1=24 \text{, then, } |Perm(R)|=24!\\\\|FR|=26-7+2=21 \text{, then, } |Perm(FR)|=21!\\$

where $|Perm(X)|=\text{number of possible permutations of the elements of X taking all at once}$

and

$|Perm(F) \cup Perm(R)| = |Perm(F)| + |Perm(R)| - |Perm(FR)|\\= 23!+24!- 21! \text{ possibilities}$

What we are looking for is the number of permutations of the 26 letters of the alphabet that do not contain the strings fish, rat or bird, or

$|Perm(\mathcal{E})|-|Perm(B)|-|Perm(F)\cup Perm(R)|\\= 26!-23!-(23!+24!- 21!)\\= 402619359782336797900800000 \text{ possibilities}$

This link contains another solved problem on permutations:

brainly.com/question/7951365

6 0

3 years ago

Solve by graphing <br><br> u=v and 6u=2v-24

Vadim26 [7]

Answer:

$u=-6 \\ \\ v=-6$

Step-by-step explanation:

In this exercise, we have two equations, namely:

$u=v \ and \ 6u=2v-24$

And we are asked to solve this problem by graphing. In this way, we can write a system of linear equations in two variables, but first of all, let's rewrite:

$u=y \\ \\ v=x$

Then:

$\left\{ \begin{array}{c}y=x\\6y=2x-24\end{array}\right.$

So here we have two lines.

The first one is:

$\boxed{y=x}$

This line passes through the origin and has a slope $m=1$

The second one is:

$6y=2x-24 \\ \\ \therefore y=\frac{2x-24}{6} \\ \\ \therefore \boxed{y=\frac{1}{3}x-4}$

This line has a slope $m=\frac{1}{3}$ and cuts the y-axis at $b=-4$

By using graph tools, we get the graph shown below, then:

$x=-6 \\ \\ y=-6 \\ \\ \\ Since \ u=y \ and \ v=x, then: \\ \\ u=-6 \\ \\ v=-6$

8 0

3 years ago

Which binomial expressions are factors of 4x3+9x2−x−6? <br><br> Select each correct answer.

lapo4ka [179]

Answer:

It is (x+ 1

Step-by-step explanation:

Because -1 is a root because 4(-1)^3 + 9(-1)^2 - (-1) - 6 = -4 + 9 + 1 - 6 = -5 + 5 = 0

4 0

3 years ago

two APS have the same common difference .the difference between their 100th terms is 100 what is the difference between their 10

Delvig [45]

Answer:

100

Step-by-step explanation:

Given that 2 ap's have same common difference

given that their 100th terms difference is 100

let the first no. of first series be a1 and second series be a2

then, a(1)100 - a(2)100=100 ---- 1

for 1st series ---- a100=a1+99d

2nd series ---- a100 = a2+99d

keep these values in (1)

then,

a1+99d - (a2+99d) = 100

a1+99d-a2-99d=100

therefore, a1-a2 =100 ------------------------------------------- 2

then the difference between their 1000th terms is

for 1st series --- a1000 = a1+999d

for 2nd series --- a1000 = a2+999d

their 100th terms difference is

a(1)1000-a(2)1000

a1+999d-(a2+999d)

a1+999d-a2-999d

therefore we get the value a1-a2

from (2) a1-a2 = 100

therefore the difference between their 1000th terms is 100

<h2><em><u>PLEASE MARK MY ANSWER AS BRAINLIEST!!!!!</u></em></h2><h2><em><u /></em></h2>

7 0

4 years ago

Rationalize the numerator of (√(3)-9)/4.<br><br>When I get -78/4√(3)+36. Is that correct?

Zina [86]

That's what I got. to rationalize the numerator you have to multiply by the conjugate, in this case (√3 + 9) / (√3 + 9), which is what it looks like you did.
hope this helps! if you liked this answer please rate it as brainliest!! thank you!!!

3 0

3 years ago