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3 years ago

Please answer correctly! I will mark you Brainleist!

Mathematics

2 answers:

olga_2 [115]3 years ago

4 0

The answer is V≈150.8 enjoy

Vladimir [108]3 years ago

3 0

Answer:

diameter of cone = 4 in so radius is 4/2 = 2 in

V of cone=πr2h

= 3.14 * 2 * 2 * 9

= 113.04

rounding to the nearest tenth, its 113

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–5(3 – q) + 4 = 5q – 11

mrs_skeptik [129]

Answer:

Step-by-step explanation:

–5(3 – q) + 4 = 5q – 11

-15 +5q + 4 = 5q -11

-11 + 5q = 5q - 11

+5q - 5q = -11 + 11

0=0

6 0

3 years ago

I need help I don’t understand how to do this

hichkok12 [17]

Answer:

your answer is 7 for this problem

4 0

3 years ago

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A code consists of two digit numbers chosen from 00-99 (i.E 00, 01, 02…..99) followed by two different letters of the alphabet.

Ede4ka [16]

Answer: 1/67600

Step-by-step explanation:

probability that the code is 43MZ:

Probability = (Total Required outcome / total possible outcomes)

Possible outcomes (digit) = (00,.............. ..., 99)

2.) possible outcomes (alphabet) = (A, B,............... .., Z)

P(43MZ) = P(43) × P(M) × P(Z)

P(43) = 1/100

P(M) = 1/26

P(Z) = 1/26

THEREFORE ;

P(43MZ) = (1/100) × (1/26) × (1/26) = 1/67600

4 0

4 years ago

A flat rectangular piece of aluminum has a perimeter of 62 inches. The length is 15

Salsk061 [2.6K]

Answer:

So, the required width of rectangular piece of aluminium is 8 inches

Step-by-step explanation:

We are given:

Perimeter of rectangular piece of aluminium = 62 inches

Let width of rectangular piece of aluminium = w

and length of rectangular piece of aluminium = w+15

We need to find width i.e value of x

The formula for finding perimeter of rectangle is: $Perimeter=2(Length+Width)\\$

Now, Putting values in formula for finding Width w:

$Perimeter=2(Length+Width)\\\\62=2(w+15+w)\\62=2(2w+15)\\62=4w+30\\62-30=4w\\4w=32\\w=\frac{32}{4}\\w=8$

After solving we get the width of rectangular piece :w = 8

So, the required width of rectangular piece of aluminium is 8 inches

6 0

3 years ago

2.0 is what times greater than 0.2

DENIUS [597]

it is ten times greater

4 0

4 years ago

Read 2 more answers