3 years ago

Help please I need help on this question

Mathematics

1 answer:

larisa86 [58]3 years ago

6 0

The answer to this is 1,150

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In a normal distribution, most numbers in the data set fall within one standard deviation of the mean. True or False

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True

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3 years ago

18°+2, what is the value of y?

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Were is y located at?

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9340.00 is invested into an account that earns 8 1/2% simple interest for 15 years. What is the interest earned and what is the

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9340.00dollars will be 1,200,190 dollars after 15 years over a respected 8.5% interest.

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9340(1+8.5×15)

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3 years ago

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

ddd [48]

Answer:

$f'(x) = 4x^2 - 3$ for $x \le -3$

Step-by-step explanation:

See attachment for proper question

Given

$f(x) = -\frac{1}{2}\sqrt{x + 3}$

For

$x \ge -3$

Required

Determine the inverse function

$f(x) = -\frac{1}{2}\sqrt{x + 3}$

Replace f(x) with y

$y = -\frac{1}{2}\sqrt{x + 3}$

Swap the positions of x and y

$x = -\frac{1}{2}\sqrt{y + 3}$

Multiply both sides by -2

$-2 * x =-2 * -\frac{1}{2}\sqrt{y + 3}$

$-2x =\sqrt{y + 3}$

Square both sides

$(-2x)^2 =(\sqrt{y + 3})^2$

$4x^2 =y + 3$

Make y the subject

$y = 4x^2 - 3$

The inverse has been solved. So, we need to replace y with f'(x)

$f'(x) = 4x^2 - 3$

Next, is to determine the interval

$x \ge -3$

Change inequality to $\le$

$x \le -3$

Hence, the inverse function is:

$f'(x) = 4x^2 - 3$ for $x \le -3$

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3 years ago

Find the mean, median, and mode for the following data set.<br><br> 3, 8, 10, 14, 14, 17

zalisa [80]

Answer:

Mean = 11

Median = 12

Mode = 14

Step-by-step explanation:

I hope this helped!

8 0

3 years ago