CAN SOMEONE HELP ME ASAP THANK YOU SO MUCH :{

7/12% of a quantity is equal to what fraction of the quantity?

serg [7]

Answer:

12 = 22 × 3

Step-by-step explanation:

7 0

3 years ago

In triangle ABC, P is a centroid on a median AD. If AD=33 and AP>PD find AP

jasenka [17]

Answer:

AP = 22

Step-by-step explanation:

In a triangle, the centroid divides the median in the ratio 2:1.

It is given that AD is the median and AD = 33

It is also given that P is the centroid on the median AD.

Therefore, P divides AD in the ratio 2:1.

$\frac{AP}{PD} =\frac{2}{1}$

AP = 2k and PD = k

AD = 33

AP + PD = 33

2k + k = 33

3k = 33

k = 11

So, AP = 2k = 2(11) = 22

7 0

3 years ago

Create a square root with at least 3 transformations

Fittoniya [83]

Answer:

Step-by-step explanation:

Start with f(x) = √x.

1) Multiplying this by "c" will either stretch or shrink the graph: stretch, if "c" is > 0; shrink, if 0 < c < 1.

2) Replacing 'x' with 'x - h' will translate the original graph h units to the right, if h is positive;

Replacing 'x' with 'x - h' will translate the original graph h units to the left, if h is negative.

3) Adding k to f(x) = √x will translate the graph upward by k units if k is positive and downward by k units if k is negative.

8 0

2 years ago

A fair coin is to be tossed 20 times. Find the probability that 10 of the tosses will fall heads and 10 will fall tails, (a) usi

lbvjy [14]

Using the distributions, it is found that there is a:

a) 0.1762 = 17.62% probability that 10 of the tosses will fall heads and 10 will fall tails.

b) 0% probability that 10 of the tosses will fall heads and 10 will fall tails.

c) 0.1742 = 17.42% probability that 10 of the tosses will fall heads and 10 will fall tails.

Item a:

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

20 tosses, hence $n = 20$ .
Fair coin, hence $p = 0.5$ .

The probability is P(X = 10), thus:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{20,10}.(0.5)^{10}.(0.5)^{10} = 0.1762$

0.1762 = 17.62% probability that 10 of the tosses will fall heads and 10 will fall tails.

Item b:

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with $\mu = np, \sigma = \sqrt{np(1-p)}$ .

The probability of an exact value is 0, hence 0% probability that 10 of the tosses will fall heads and 10 will fall tails.

Item c:

For the approximation, the mean and the standard deviation are:

$\mu = np = 20(0.5) = 10$

$\sigma = \sqrt{np(1 - p)} = \sqrt{20(0.5)(0.5)} = \sqrt{5}$

Using continuity correction, this probability is $P(10 - 0.5 \leq X \leq 10 + 0.5) = P(9.5 \leq X \leq 10.5)$ , which is the p-value of Z when X = 10.5 subtracted by the p-value of Z when X = 9.5.