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Dmitry [639]
3 years ago
10

Javier worked 2.4 hours on Monday. Javier worked twice as long on Tuesday than he did on Monday. His pay rate is $10.25 an hour.

How much will he be paid, in dollars, for the two days?​
Mathematics
1 answer:
svetlana [45]3 years ago
3 0

Answer:

73.8$

Step-by-step explanation:

Total hours:

2.4 + 2 * 2.4 = 7.2 hours

For the two days he will be paid:

(7. 2 hours) * (10.25 $/hour) =73.8$

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zubka84 [21]
The solution to the equation would be 21.5

Why?

If you do the equation backwards

30 - 8.5 = x

You would get 21.5
You can plug it into the first equation to check!

:)


8 0
4 years ago
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David can type 90 words a minute.<br> How many words can be typed in 9.5 minutes?
artcher [175]

Answer:

855

Step-by-step explanation:

90x9.5=855

4 0
2 years ago
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If tan θ =(√3)/3, 0◦&lt; θ &lt; 360◦,
svetlana [45]
Arctan (√3 /3) = 30°. = π/6 rad

That is the value searched, in degrees and radians.

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3 0
3 years ago
Use the diagram of the right triangle above and round your answer to the nearest hundredth.
Yakvenalex [24]
Answer: a = 23 ft.

Reasoning:

The question asks for the value of the leg a, given the tangent of the opposite angle and the length of the adjacent-leg, b.

The ratio that relates the three parameters is:

tan(A) = opposite-leg / adjacent-leg = a / b = a / 23 ft

Solve for a, wich is the unknown:

a = 23ft * tan(A) = 23ft * 1.0 = 23 ft

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7 0
3 years ago
a fisherman travels 9mi downstream with the current in the same time he travels 3 mi upstream against the current. if the speed
netineya [11]

Answer:

10 mph

Step-by-step explanation:

speed of boat in still water = x

speed of current = 5

speed of boat with current (downstream) = x + 5

speed of boat against current (upstream) = x - 5

distance downstream = 9

distance upstream = 3

time = t

speed = distance/time

distance = speed × time

downstream:

9 = (x + 5)t

upstream:

3 = (x - 5)t

9 = xt + 5t

3 = xt - 5t

9 = xt + 5t

-3 = -xt + 5t

-----------------

6 = 10t

t = 0.6

9 = (x + 5)0.6

15 = x + 5

x = 10

5 0
2 years ago
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