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vagabundo [1.1K]
2 years ago
15

please do my question u get more points if the answer is right. if inappropriate you get reported NO LINKS and please EXPLAIN

Mathematics
1 answer:
Lunna [17]2 years ago
5 0

Answer:

600

Step-by-step explanation:

Well, first you need to make a proportion which will be \frac{x}{6,000} = \frac{10}{100}

x is what we need to find

6,000 is the total people who voted

10% is the percent of 18 to 29 years old

and 100% represents the circle graph because all circle graphs equal 100%

First, we use the cross multiply method, for instance, 6,000×10=60,000

Next, divide 60,000÷100 which is 600.

Therefore there are 600, 18 to 29 year olds who voted in the election.

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If a bookworm can finish eating 23.68 pages of a book in 3.2 days, how much can it eat in
blagie [28]

Answer:

7.4

Step-by-step explanation:

just divide it by 3.2

4 0
3 years ago
OKAY i CANT EVEN FIGURE THIS ONE OUT NEED HELP.<br> -3 (5 – 2y)
inessss [21]

negative multiplied by positives = negative numbers

3 x 5 = -15

negative multiplied by a negative = a positive number

-3 x -2y = +6y

so combine both gets -15 +6y

or a better way to write it is 6y-15

5 0
3 years ago
Can someone help Solve these 2 questions for me? It's about Slope Intercept Forms.
Hitman42 [59]

Answer:

9.) The slope is 3 and the y-intercept is -5

10.) y = 0.25x -11

Hope this helped!

Stay safe! <3

3 0
2 years ago
Can anyone please help with this.
Eddi Din [679]
The first question answer is 21*10^7
The second question answer is 5*10^2
7 0
3 years ago
Five males with an​ X-linked genetic disorder have one child each. The random variable x is the number of children among the fiv
Dahasolnce [82]

Answer and Explanation:

Given : Five males with an​ X-linked genetic disorder have one child each. The random variable x is the number of children among the five who inherit the​ X-linked genetic disorder.

To find :

a. Does the table show a probability distribution?

b. Find the mean and standard deviation of the random variable x.

Solution :

a) To determine that table shows a probability distribution we add up all six probabilities if the sum is 1 then it is a valid distribution.

\sum P(X)=0.029+0.147+0.324+0.324+0.147+0.029

\sum P(X)=1

Yes it is a probability distribution.

b) First we create the table as per requirements,

x      P(x)         xP(x)           x²            x²P(x)

0    0.029         0              0                0

1     0.147        0.147           1              0.147

2    0.324       0.648         4              1.296

3    0.324       0.972         9              2.916

4    0.147        0.588        16              2.352

5    0.029       0.145         25            0.725

   ∑P(x)=1      ∑xP(x)=2.5               ∑x²P(x)=7.436

The mean of the random variable is

\mu=\sum xP(x)=2.5

The standard deviation of the random sample is

Variance=\sigma^2

\sigma^2=\sum x^2P(x)-\mu^2

\sigma^2=7.436-(2.5)^2

\sigma^2=7.436-6.25

\sigma^2=1.186

\sigma=\sqrt{1.186}

\sigma=1.08

Therefore, The mean is 2.5 and the standard deviation is 1.08.

5 0
2 years ago
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