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Dafna11 [192]
2 years ago
5

HELP PLEASE

Mathematics
1 answer:
Hoochie [10]2 years ago
6 0
If you had values instead of algebraic expressions, you would find the area of the patio and subtract that from the area of the yard. Even though you don't have values, you can still find the area and subtract by expanding and simplifying:
(8x + 2)(6x + 3)
8x × 6x = 48x²
8x × 3 = 24x
2 × 6x = 12x
2 × 3 = 6
So you get 48x² + 36x + 6 as your area of the yard

(x + 5)(3x + 1)
x × 3x = 3x²
x × 1 = x
5 × 3x = 15x
5 × 1 = 5
So the area of the patio is 3x² + 16x + 5

(48x² + 36x + 6) - (3x² + 16x + 5)
48x² - 3x² = 45x²
36x - 16x = 20x
6 - 5 = 1

So your answer is D. 45x² + 20x + 1. I hope this helps!

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Answer:

A)

Note that              

             

Lower Bound = X - z(alpha/2) * s / sqrt(n)              

Upper Bound = X + z(alpha/2) * s / sqrt(n)              

             

where              

alpha/2 = (1 - confidence level)/2 =    0.025          

X = sample mean =    1723.4          

z(alpha/2) = critical z for the confidence interval =    1.959963985          

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Thus,              

             

Lower bound =    1691.355235          

Upper bound =    1755.444765          

             

Thus, the confidence interval is              

             

(   1691.355235   ,   1755.444765   ) [ANSWER]

*********************

b)

We assumed taht the distirbution of these observations is approximately normally distributed.

*******************

c)

Yes, because the values are not far away from each other.

4 0
3 years ago
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Answer:

4

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