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3 years ago

HELP PLEASE

1 answer:

6 0

If you had values instead of algebraic expressions, you would find the area of the patio and subtract that from the area of the yard. Even though you don't have values, you can still find the area and subtract by expanding and simplifying:
(8x + 2)(6x + 3)
8x × 6x = 48x²
8x × 3 = 24x
2 × 6x = 12x
2 × 3 = 6
So you get 48x² + 36x + 6 as your area of the yard

(x + 5)(3x + 1)
x × 3x = 3x²
x × 1 = x
5 × 3x = 15x
5 × 1 = 5
So the area of the patio is 3x² + 16x + 5

(48x² + 36x + 6) - (3x² + 16x + 5)
48x² - 3x² = 45x²
36x - 16x = 20x
6 - 5 = 1

So your answer is D. 45x² + 20x + 1. I hope this helps!

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Time is C. 50 seconds

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The population of bacteria at time t here is given by

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3 years ago

What is the slope of the line that passes through the points (1, -6) and (-8, 9) ?Write your answer in simplest form.

Dmitry [639]

Answer:

5/-3

Step-by-step explanation:

The slope formula is rise/run.

If you graph this, the two points make a line that slopes downwards. The higher point is in the negative axis, which means that the run will be negative.

you rise up 15 points from the first point (1,-6) to get to the same level as the second point. (-8,9). This is your rise.

You go over to the other point, this is your run. The run is -9.

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we can simplify this fraction.

5/-3 is your final answer.

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3 years ago

Problem 1:

wariber [46]

Answer:

x=1/6

Step-by-step explanation:

3x+4=9x+3

isolate x

1=6x

1/6=x

6 0

2 years ago

Read 2 more answers

Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (

kirill115 [55]

Answer:

f(0,0)=ln19

Step-by-step explanation:

$f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2})$ is given as continuous function, so there exist $lim_{(x,y)\rightarrow(0,0)}f(x,y)$ and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

$f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})$