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3 years ago

choosing a card from a deck of cards numbered 10, 11, 12, ..., 25 and picking a day of the week WHAT IS THE PROBABILITY

Mathematics

1 answer:

lina2011 [118]3 years ago

3 0

12 can you tell me what I got

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How do you find the angles on this special triangle?

Rasek [7]

Answer:

it is isosceles triangle with an angle = 90. Two others angle are equal. sum of all angles in triangle is 180.

2x + 90=180 --> x=45

3 0

3 years ago

Read 2 more answers

Evaluate 4 − 0 . 2 5 g + 0 . 5 h 4−0.25g+0.5h4, minus, 0, point, 25, g, plus, 0, point, 5, h when g = 1 0 g=10g, equals, 10 and

abruzzese [7]

Not sure about the weird echo in the question but I think we're being ask to evaluate

4 - 0.25g + 0.5h

when g=10, h=5

That's

4 - 0.25(10) + 0.5(5) = 4 - 2.5 + 2.5 = 4

Answer: 4

6 0

3 years ago

Read 2 more answers

A. Original Price: $16.20

Tom [10]

Answer:

The final price is $ 22.68 And Proportional constant is 1.4

Step-by-step explanation:

Given as :

The Original price = $ 16.20

The rate of increase = 40%

Let The final price = x

Now,

Final price after increase = initial price × ( 1 + $\frac{\textrm Rate}{100}$

Or. Final price after increase = $ 16.20 × ( 1 + $\frac{\textrm 40}{100}$

Or, Final price after increase = $ 16.20 × ( 1.4 )

∴ Final price after increase = $ 22.68

Now , Proportional constant = $\frac{22.68}{16.20}$

I.e Proportional constant = 1.4

Hence The final price is $ 22.68 And Proportional constant is 1.4 Answer

4 0

3 years ago

What is the value of x in the figure below

DanielleElmas [232]

Answer:

x=9

Step-by-step explanation:

3x+9=35

3x+9-9=35-9

3x=27

3x/3=27/3

x=9

6 0

3 years ago

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a toy rocket is launched from the top of a 48 foot hill. The rockets initial upward velocity is 32 feet per second and its heigh

sdas [7]

Answer:

t = 2.11 seconds

Step-by-step explanation:

A toy rocket is launched from the top of a 48 foot hill. The rockets initial upward velocity is 32 feet per second and its height h at any given second t is modeled by the equation:

$h=-16t^2+32t+48$

Let us assume that we need to find the time by it to reach the ground. It means h = 0

$-16t^2+32t+48=0$

The above is a quadratic equation. The value of t is given by :

$t=\dfrac{-b\pm \sqrt{b^2-2ac} }{2a}\\\\t=\dfrac{-b+ \sqrt{b^2-2ac} }{2a},\dfrac{-b- \sqrt{b^2-2ac} }{2a}\\\\t=\dfrac{-32+ \sqrt{(32)^2-2\times (-16)(8)} }{2\times (-16)},\dfrac{-32-\sqrt{(32)^{2}-2\times(-16)(8)}}{2\times(-16)}\\\\t=-0.11\ s, 2.11\ s$

So, it will take 2.11 seconds to reach the ground.

6 0

3 years ago