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bearhunter [10]
3 years ago
15

choosing a card from a deck of cards numbered 10, 11, 12, ..., 25 and picking a day of the week WHAT IS THE PROBABILITY

Mathematics
1 answer:
lina2011 [118]3 years ago
3 0
12 can you tell me what I got
You might be interested in
Please help me on this question<br> thank u
mafiozo [28]
System of equations:
w=(3/2)*h          (1)
w*h=54      area (2)

w=54/h substitute into (1)
54/h=3h/2
3h²=54*2
h²= 36  (we take only positive solution)
h = √36=6
h=6 in.
w=(3/2)*h=(3/2)*6= 9
w=9 in.
correct answer is D
5 0
3 years ago
Omg please help for brainlist !!!!!!!!!!!!!!!!!!!
zhannawk [14.2K]

Answer:

f(x) is linear

g(x) is exponential

Step-by-step explanation:

A linear function will always have the same rate of change between equally distant points, while an exponential function will have an increasingly large rate of change between equally distant points.

First, look at f(x). All these points are equally distant at 2 units apart on the x-axis, so they can be directly compared:

(-38)-(-18)=-20\\(-58)-(-38)=-20\\(-78)-(-58)=-20

All of these points are the same distance apart on the y, so f(x) must be a linear function.

Now look at g(x). These are also all equally distant at only 1 unit apart.

30-10=20\\90-30=60\\270-90=180

These are very clearly not the same distance apart on the y, so g(x) must be the exponential function.

6 0
3 years ago
How long will it take to administer 1000 cc at a drop factor of 15 drop/ml and a drip rate of 50 drop/min
gayaneshka [121]
First, we are going to determine the number of drops that needs to be administered by dividing the total volume by the volume per drop. Since, 1 cc (cm³) is equal to 1 mL then, 1000 cc is equal to 1000 mL.

   n = (1000 mL)(15 drop/1 mL) = 15000 drops

Then, divide the number of drops by the number of drops per minute.

   N = (15000 drops)/ (50 drop/min) = 300 mins

Answer: 300 mins or 5 hours
5 0
3 years ago
At the bright-as-day light bulb factory, 5 out of each 136 bulbs produced are defective. If the daily production is 2720 bulbs,
lions [1.4K]

Answer:

100 lightbulbs

Step-by-step explanation:

Basically find the percentage of lightbulbs that are bad. 5/136. So about 3. 6 percent. I'm going to use a more exact form of this percent for my calculations though. Now use the decimal for of this (0.036....) and multiply it by 2720. Using my exact decimal, the answer just so happened to be exactly 100. So there will be 100 defective lightbulbs per day. (Teachers are a stickler for units, so don't forget them if it's for a teacher)

Hope this helps!

4 0
3 years ago
the area of a rectangle is 90 in2^. the ratio of the length to the width is 5:2. find the length and the width
-BARSIC- [3]

Length and width of rectangle is 15 inches and 6 inches respectively

<h3><u>Solution:</u></h3>

Given that area of a rectangle is 90 square inch

Ratio of length to the width = 5: 2.

Need to determine length and width of rectangle.  

As ratio of length to the width is 5 : 2

Lets assume length of rectangle = 5x inches and width of rectangle = 2x inches.

<em><u>The formula for area of rectangle is given as:</u></em>

\text { Area of rectangle }=\text { length of rectangle } \times \text { width of rectangle}

Substituting the given value of area of rectangle and assumed value of length and width of rectangle we get:

\begin{array}{l}{90=5 x \times 2 x} \\\\ {=>90=10 x^{2}}\end{array}

On solving the above expression for x we get

\begin{array}{l}{=>\frac{90}{10}=x^{2}} \\\\ {=>x^{2}=9} \\\\ {=>x=\sqrt{9}=3}\end{array}

\begin{array}{l}{\text { Length of rectangle }=5 \times x=5 \times 3=15 \text { inches }} \\\\ {\text { Width of rectangle }=2 \times} x=2 \times} 3=6 \text { inches }}\end{array}

Hence length and width of rectangle is 15 inches and 6 inches.

4 0
4 years ago
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