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3 years ago

Percent of change old 32 new 24

Mathematics

1 answer:

stiks02 [169]3 years ago

8 0

32 - 24 = 8
32 x 25% =8

25%

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The graph of f(x) is obtained by reflecting the graph of g(x)=3|x| over the x-axis.

Alinara [238K]

Answer:

Choice B), $f(x) = -3|x|$ .

Step-by-step explanation:

Each point on the graph of $g(x)$ can be represented as $(x, g(x))$ .

When the graph of $g(x)$ is reflected over the x-axis, each point on the graph is also reflected over the x-axis. The x-coordinate of each point will not change but the sign in front of the y-coordinate will flip. For example, $1$ (same as $+1$ ) will become $-1$ , and vice versa. In general, $(x, g(x))$ will become $(x, -g(x))$ .

On the other hand, points on the graph of $f(x)$ can be represented as $(x, f(x))$ . $f(x)$ is the reflection of $g(x)$ , so $(x, -g(x))$ and $(x, f(x))$ shall be equivalent. In other words,

$f(x) = -g(x) = - 3|x|$ .

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2 years ago

A cylindrical soup can has a radius of 1.2 in. and is 6 in. tall. What's the volume?

Sergio [31]

Answer:

Volume= 27. 12inches³

Step-by-step explanation:

to solve this question lets write out the parameters given

radius of the cylinder = 1.2 inches

height of the cylinder = 6 inches

volume of the cylinder = ?

solution

the fomular to find the volume of a cylinder is given to be

Volume= πr²h

Volume= 3.14 × ( 1.2)² × 6

Volume= 3.14 × 1.44 × 6

Volume= 27. 12inches³

therefore the volume of the cylinder equals to 27. 12inches³

7 0

2 years ago

How many different ways are there to choose a subset of the set {1,2,3,4,5,6} so that the product of the members of the subset i

zvonat [6]

You have to pick at least one even factor from the set to make an even product.

There are 3 even numbers to choose from, and we can pick up to 3 additional odd numbers.

For example, if we pick out 1 even number and 2 odd numbers, this can be done in

$\dbinom 31 \dbinom 32 = 3\cdot3 = 9$

ways. If we pick out 3 even numbers and 0 odd numbers, this can be done in

$\dbinom 33 \dbinom 30 = 1\cdot1 = 1$

way.

The total count is then the sum of all possible selections with at least 1 even number and between 0 and 3 odd numbers.

$\displaystyle \sum_{e=1}^3 \binom 3e \sum_{o=0}^3 \binom 3o = 2^3 \sum_{e=1}^3 \binom3e = 8 \left(\sum_{e=0}^3 \binom3e - \binom30\right) = 8(2^3 - 1) = \boxed{56}$