Answer:
13
Step-by-step explanation:
I mean, they both do. i am not 100% sure, but im pretty sure. Hope this helps!
1) slope is 6 and y-intercept is ( 0,5) y = mx + b, m = 6, b = 5 y = 6x + 5 2)line passes through the points ( 3,6) and ( 6,3 ) First find the slope: m = (3-6)/(6-3) = -3/3 = -1 y = -x + b Plug in one of the given points (x,y) and find b 6 = -3 + b 9 = b <span> y = -x + 9</span> a horizontal line that passes through the point ( -1,7)Horizontal lines have a constant y-value and formaty = c where c is a constant number. y = 7 y=-3x+3x intercept: set y = 0 and solve for x0 = -3x + 33x = 3x = 1x-intercept: (1, 0) y-intercept: set x = 0 and solve for yy = -3(0) + 3y = 3y-intercept: (0,3) y=0,5x-1Is this two equations? The line y=0 has y-intercept at (0,0)The x-intercept is the entire x-axis y=5x-1x -intercept: Set y = 0 and solve for x y-intercept: Set x = 0 and solve for y
<h3>
Answer: -15 and 2</h3>
You find this through trial and error.
A much more efficient way is to solve x^2-13x-30 = 0 using the quadratic formula. You'll find the two solutions to be x = 15 and x = -2
Going from those solutions, we get x-15 = 0 and x+2 = 0 which then turn into (x-15)(x+2) = 0 through the zero product property.
