Answer:
Since 2 or x-2= 0 is a zero of the function we divide it by the function to get the other factors
x³ + 2x² - 5x - 6 ÷ x -2
We get
(x + 3)(x+1) = 0
Therefore x³ + 2x² - 5x - 6 in factored form is
(x - 2)(x + 3)(x + 1)
Hope this helps.
Simplify the following:
((8 x^3 y^2 a^2 b^4)/4)^(-2)
8/4 = (4×2)/4 = 2:
(2 x^3 y^2 a^2 b^4)^(-2)
Multiply each exponent in 2 x^3 y^2 a^2 b^4 by -2:
(x^(-2×3) y^(-2×2) a^(-2×2) b^(-2×4))/(2^2)
-2×3 = -6:
(x^(-6) y^(-2×2) a^(-2×2) b^(-2×4))/2^2
-2×2 = -4:
(y^(-4) a^(-2×2) b^(-2×4))/(2^2 x^6)
-2×2 = -4:
(a^(-4) b^(-2×4))/(2^2 x^6 y^4)
-2×4 = -8:
b^(-8)/(2^2 x^6 y^4 a^4)
2^2 = 4:
Answer: 1/(4 x^6 y^4 a^4 b^8) thus the answer is A
The first statement: a function is always a function but a relation is not always a function.
Answer:
true
Step-by-step explanation:
im really not sure. it just sounds true
