All categories

3 years ago

Pls help i dont understand :( will give Brainliest + 25 Points

Mathematics

1 answer:

svetoff [14.1K]3 years ago

7 0

Answer:

it is d

Step-by-step explanation:

You might be interested in

Bernie bought a pair of shoes at the store when they were having a 30% off sale. If the

Ne4ueva [31]

It’s $12.60 dollars!!!

3 0

2 years ago

A square painting painting is surrounded by a frame. the outside edges of the frame are 3 inches in length, and the frame is 3 i

sdas [7]

Answer:

Area = 36 $inches ^ 2$

Step-by-step explanation:

There must be an error with the statement, because it is strange that the length of the frame is equal to its thickness.

Assuming that the data supplied is correct, we can do the following procedure.

Let's call L the length of the frame.

We know how much each side of the square measures.

L = 3 inches

We also know that the thickness (s) is:

s = 3 inches.

Then the area of the frame is equal to:

Area = Perimeter * thickness

Area = 4L*s

Area = 3*4*3

Area = 36 $inches ^ 2$

3 0

2 years ago

Without graphing, determine the range of the runction f(x)=4|x+6|-5

Aneli [31]

Since is a positive a value (4) we know that the graph opens upward. -5 represents how far up or down the “vertex” is of the absolute value graph. This means that the range is -5

7 0

3 years ago

98 - 5q for q = 7 help

Molodets [167]

you have to multiply the 5 and the 7 and you get 35 then subtract 98 and 35 and you get 63

3 0

3 years ago

Read 2 more answers

The volume of water and a rectangle swimming pool can be modeled by the function v(x)=x^3+13x-210. If the depth of the pool is g

S_A_V [24]

Answer:

Required,

$L=\frac{3+\sqrt{37}}{2}-\frac{144}{x-3}$

$W=\frac{3-\sqrt{37}}{2}-\frac{144}{x-3}$

Step-by-step explanation:

Given volume and depth respectively,

$V(x)=x^3+13x-210$ and $x-3$

To find length and width of the rectanglular swiming pool we know,

Volume=length $\times$ height $\times$ depth.

Let depth=D=x-3, length=L, width=W, then

$V=DLW$

$x^3+13x-210= LW(x-3)$

$LW=\frac{x^3+13x-210}{x-3}$

After divide we will get $x^2-3x-22$ with remainder -144.

Thus,

$x^3+13x-210=(x^2-3x-22)(x-3)-144=(x-3)LW$

Now to find root of,

$x^2-3x-144=\frac{3\pm\sqrt{9+88}}{2}=\frac{3\pm \sqrt{37}}{2}$

Thus,

$L=\frac{3+\sqrt{37}}{2}-\frac{144}{x-3}$

$W=\frac{3-\sqrt{37}}{2}-\frac{144}{x-3}$

5 0

2 years ago