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3 years ago

Does bin width matter when it comes to histograms? Why or why not?

Mathematics

1 answer:

maw [93]3 years ago

4 0

Answer:

Avoid histograms with small bin widths that group data into lots of bins. A histogram constructed with small bin widths will show the distribution as a “pancake.” so no it does not help us see the pattern in the data.

Step-by-step explanation:

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Can you guys help me

natita [175]

Answer:

would be A

Step-by-step explanation:

because bisecting means both sides equal the same. so 4x-12 times two is 8x-24. Hope this helps

4 0

4 years ago

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(2(n+1)-1)^2-(2n-1)^2 simplified

Westkost [7]

Answer: 8n

Let's simplify step-by-step.

(2(n+1)−1)2−(2n−1)2

Distribute:

=4n2+4n+1+−4n2+4n+−1

Combine Like Terms:

=4n2+4n+1+−4n2+4n+−1

=(4n2+−4n2)+(4n+4n)+(1+−1)

=8n

7 0

3 years ago

Suppose that a college determines the following distribution for X = number of courses taken by a full-time student this semeste

lidiya [134]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$ In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$ And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

$Sd(X) =\sqrt{0.8924} =0.9447$

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

Solution to the problem

For this case we have the following distribution given:

X 3 4 5 6

P(X) 0.07 0.4 0.25 0.28

We can calculate the mean with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$

In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$

And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

$Sd(X) =\sqrt{0.8924} =0.9447$

3 0

3 years ago

Which quadrilateral will always have 4- fold reflectional symmetry

Talja [164]

I'm pretty sure it's the square. The square can be divided into 4 equal parts, each part able to reflect each other.

5 0

4 years ago

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The Pythagorean theorem can be used for any type of triangle. true or false

notka56 [123]

False. Only right triangles.

8 0

3 years ago