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dimaraw [331]
2 years ago
7

Find the equation ( in slope - intercept form ) of the line with the given slope that passes through the point with the given co

ordinates . slope : 4/3 ordered pair : (1, 4)
help pls!
Mathematics
1 answer:
svlad2 [7]2 years ago
5 0

Answer:

  y = 4/3x +8/3

Step-by-step explanation:

The point-slope form is ...

  y -k = m(x -h) . . . . . . . line with slope m through point (h, k)

For the given point and slope, this is ...

  y -4 = 4/3(x -1)

Adding 4 and eliminating parentheses, you have ...

  y = 4/3x -4/3 +4

  y = 4/3x +8/3

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Step-by-step explanation:

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Answer:

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Vertex (4, -13) y = x^2 - 8x + 3 x-coordinate of vertex: x = -b/(2a) = 8/2 = 4 y-coordinate of vertex: y(4) = 16 - 32 + 3 = -13 Vertex (4, -13) To find y-intercepts, make x = 0 --> y = 3 To find x-intercepts, solve the quadratic equation y = 0 Use the improved quadratic formula D = d^2 = b^2 - 4ac = 64 - 12 = 52 --> d = +- 2sqrt13 There are 2 x-intercepts (2 real roots): x = -b/(2a) +- d/(2a) = 8/2 +- (2sqrt13)/2 = 4 +- sqrt13 graph{x^2 - 8x + 3 [-40, 40, -20, 20]}

Step-by-step explanation:

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