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2 years ago

6

Determine whether y=2x^3 represents an exponential function.

1 answer:

Soloha48 [4]2 years ago

7 0

Answer:

This is not an exponential function.

Step-by-step explanation:

x would have to be the exponent for it to be an exponential function.

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Which sentence correctly compares the number of 1 4 4 1 -pound and 1 2 2 1 -pound packages that the deli can slice from a 12

frutty [35]

The statements aren't given; however the number of 1/2 and 1/4 - pound package have been calculated below.

Answer:

Step-by-step explanation:

Given :

A 12 pound block :

Number of 1/2 pound packages that can be obtained :

12 ÷ 1/2 ;

12 * 2/1 = 24 (1/2 - Pound package) can be obtained.

Number of 1/4 pound package that can be obtained :

12 ÷ 1/4

12 * 4 /1 = 48 (1/4 - Pound package) can be obtained

We can obtain twice the number of 1/2 - pound package by using the 1/4 - pound slicing.

7 0

2 years ago

Solve quadratic equation 10x^2+x-2=0

zhuklara [117]

Answer:

$\{-\frac{1}{2} \} \cup \{\frac{2}{5}\}$

Step-by-step explanation:

$10x^2 + x - 2 = 0; \\ a = 10, b = 1, c = -2; \\ D = b^2 - 4ac = 1^2 - 4 * 10 * (-2) = 1 + 80 = 81 = 9^2, > 0; \\ x_{1, 2} = \frac{-b \pm \sqrt{D}}{2a} = \frac{-1 \pm \sqrt{9^2}}{2 * 10} = \frac{-1 \pm 9}{20} = \left \ [ {{\frac{-1 - 9}{20} = -\frac{10}{20} = -\frac{1}{2} } \atop {\frac{-1 + 9}{20} = \frac{8}{20} = \frac{2}{5}}} \right.$

8 0

1 year ago

How many ducks do you see?

tekilochka [14]

Answer:

13

Step-by-step explanation:

count the big ducks first

then go back and count the smaller ones

6 0

3 years ago

lions [1.4K]

Answer:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

Step-by-step explanation:

Given

$n = 125$

See attachment for proper table

Required

Complete the table

Experimental probability is calculated as:

$Pr = \frac{Frequency}{n}$

We use the above formula when the frequency is known.

For result of roll 2, 4 and 6

The frequencies are 13, 29 and 6, respectively

So, we have:

$Pr(2) = \frac{13}{125} = 0.104$

$Pr(4) = \frac{29}{125} = 0.232$

$Pr(6) = \frac{6}{125} = 0.048$

When the frequency is to be calculated, we use:

$Pr = \frac{Frequency}{n}$

$Frequency = n * Pr$

For result of roll 3 and 5

The probabilities are 0.144 and 0.296, respectively

So, we have:

$Frequency(3) = 125 * 0.144 = 18$

$Frequency(5) = 125 * 0.296 = 37$

For roll of 1 where the frequency and the probability are not known, we use:

$Total \ Frequency = 125$

So:

Frequency(1) added to others must equal 125

This gives:

$Frequency(1) + 13 + 18 + 29 + 37 + 6 = 125$

$Frequency(1) + 103 = 125$

Collect like terms

$Frequency(1) =- 103 + 125$

$Frequency(1) =22$

The probability is then calculated as:

$Pr(1) = \frac{22}{125}$

$Pr(1) = 0.176$

So, the complete table is:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

5 0

2 years ago

What is the additive inverse of 0?

jenyasd209 [6]

Answer:

The additive inverse of 0 is 0.

3 0

2 years ago

Read 2 more answers