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2 years ago

12

A bird's nest is 12 feet above the ground. A mole's den is 12 inches below the ground. What is the difference in height of these

two positions?

1 answer:

zysi [14]2 years ago

8 0

Answer:

13ft

Step-by-step explanation:

12in = 1ft the difference in height is 13ft

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The product of a number y and 3 is 6

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y=2

Step-by-step explanation:

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A skirt costs $20 more than the blouse. the skirt costs $65. what is the price of the blouse. write an equation. then solve the

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$65 - $20
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$45=the blouse

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Which of the following shows 2x3y-3x2+7yx-12y written in standard form

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2x^(3)y+7xy-3x^(2)-12y

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3 years ago

Question 7 of 10

solniwko [45]

Answer:

what may be true

Step-by-step explanation:

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2 years ago

A ball is thrown directly up in the air from a height of 5 feet with an initial velocity of 60 ft/s. Ignoring air resistance, ho

Mice21 [21]

Answer:

3.8 seconds

Step-by-step explanation:

Given equation

$h= -16t^2 + 60t + 5$

When the ball hits the ground then height is 0

So we replace h with 0 and solve for t

$0= -16t^2 + 60t + 5$

a= -16 , b= 60 and c= 5

Apply quadratic formula to solve for t

$t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

= $\frac{-60+\sqrt{60^2-4\left(-16\right)\cdot \:5}}{2\left(-16\right)}[/tex[tex]=\frac{-60+-\sqrt{3920}}{-32}$

$=\frac{-60+-28\sqrt{5}}{-32}$

$=\frac{4(-15+-7\sqrt{5})}{-32}$

$=\frac{(-15+-7\sqrt{5})}{-8}$

Now make two fractions and solve for x

t= $-\frac{7\sqrt{5}-15}{8}$ =-0.0815

t= $\frac{7\sqrt{5}+15}{8}$ =3.83

So answer is 3.8 seconds

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3 years ago