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garik1379 [7]
2 years ago
6

Math Please Hurry Im smooth brain

Mathematics
2 answers:
rosijanka [135]2 years ago
8 0
1 yes
2 no
3 no
4 no
5 yes
Klio2033 [76]2 years ago
6 0

Answer:

see below

Step-by-step explanation:

1. yes

2. no, 4.82 x 10^4

3, no, 9.9 x 10^-4

4. no, 3.6 x 10^6

5. yes

6. no, 7.8 x 10^-4

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When a frequency distribution is exhaustive, each individual, object, or measurement from a sample or population must appear in
KiRa [710]

Answer:

a. True

Step-by-step explanation:

The frequency distribution is a summary of the gathered data set, in which the interval of values is divided into classes.

A requirement for a frequency distribution is for the classes to be mutually exclusive and exhaustive. That is, each individual, object, or measurement in the data set must belong to <em>one and only one</em> class.

Then, we can conclude that each individual, object, or measurement must appear in at least one (in fact, only in one) category or class.

4 0
3 years ago
A
GREYUIT [131]
The answer is D. First, it is the segment addition postulate because the two segments make up the whole. Second, it's substitution because you are substituting EF + FG for FH.

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8 0
3 years ago
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Tomtit [17]
I believe the answer is Chord AB
3 0
2 years ago
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A Leopoldo su Maestra l le pidió que calcular el perímetro de un rectángulo que tiene las medidas que se indican en el dibujo cu
guapka [62]

Answer:

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Step-by-step explanation:

7 0
2 years ago
In Exercises 5-7, find all the exact t-values for which the given statement is true,
bearhunter [10]

Answer:  See Below

<u>Step-by-step explanation:</u>

NOTE: You need the Unit Circle to answer these (attached)

5) cos (t) = 1

Where on the Unit Circle does cos = 1?

Answer: at 0π (0°) and all rotations of 2π (360°)

In radians:     t = 0π + 2πn

In degrees:   t = 0° + 360n

******************************************************************************

6)\quad sin (t) = \dfrac{1}{2}

Where on the Unit Circle does   sin = \dfrac{1}{2}

<em>Hint: sin is only positive in Quadrants I and II</em>

\text{Answer: at}\  \dfrac{\pi}{6}\ (30^o)\ \text{and at}\ \dfrac{5\pi}{6}\ (150^o)\ \text{and all rotations of}\ 2\pi \ (360^o)

\text{In radians:}\ t = \dfrac{\pi}{6} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{6} + 2\pi n

In degrees:    t = 30° + 360n  and  150° + 360n

******************************************************************************

7)\quad tan (t) = -\sqrt3

Where on the Unit Circle does    \dfrac{sin}{cos} = \dfrac{-\sqrt3}{1}\ or\ \dfrac{\sqrt3}{-1}\quad \rightarrow \quad (1,-\sqrt3)\ or\ (-1, \sqrt3)

<em>Hint: sin and cos are only opposite signs in Quadrants II and IV</em>

\text{Answer: at}\  \dfrac{2\pi}{3}\ (120^o)\ \text{and at}\ \dfrac{5\pi}{3}\ (300^o)\ \text{and all rotations of}\ 2\pi \ (360^o)

\text{In radians:}\ t = \dfrac{2\pi}{3} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{3} + 2\pi n

In degrees:    t = 120° + 360n  and  300° + 360n

4 0
3 years ago
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