Their slopes would be the same but their positions or points ( if the lines were on a graph) would be different.
Answer:
The real zeros of f(x) are x = 0.3 and x = -3.3.
Step-by-step explanation:
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots
such that
, given by the following formulas:
In this problem, we have that:

So

The real zeros of f(x) are x = 0.3 and x = -3.3.
3x4=12 12x5=60 60x6=360 360x7=2,530 2,530x9=22,690
Answer: the awnser is c, if it is not, that would be weard bc i just did this one
step 1
we have that
44=(1/2)[180-arc} ------> by exterior angle
solve for arc
88=180-arc
arc=180-88
arc=92 degrees
give me a minute to draw a figure with letters to better understand the problem
we have that
x+?=180 degrees -------> by form a linear pair (supplemenatry angles)
x=arc=92 degrees ------> by central angle
so
?=180-92
?=88 degrees
therefore
<h2>the missing angle is 88 degrees</h2>